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javascript - 在节点边缘对齐标记 D3 强制布局

转载 作者:数据小太阳 更新时间:2023-10-29 06:00:23 26 4
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我正在尝试实现 d3 力布局,但无法弄清楚如何以正确的方式放置我的链接标记。

这是我到目前为止得到的:

var links = force_data.force_directed_data.links;

var nodes = {};

// Compute the distinct nodes from the links.
links.forEach(function (link) {
link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});

console.log(nodes);

var width = 1000,
height = 1000;

var force = d3.layout.force()
.nodes(d3.values(nodes))
.links(links)
.size([width, height])
.linkDistance(300)
.charge(-120)
.friction(0.9)
.on("tick", tick)
.start();

var svg = d3.select("#force-graph").append("svg")
.attr("width", width)
.attr("height", height);

// Per-type markers, as they don't inherit styles.
svg.append("defs").selectAll("marker")
.data(["dominating"])
.enter().append("marker")
.attr("id", function (d) {
return d;
})
.attr("viewBox", "0 -5 10 10")
.attr("refX", 15)
.attr("refY", -1.5)
.attr("markerWidth", 12)
.attr("markerHeight", 12)
.attr("orient", "auto")
.append("path")
.attr("d", "M0,-5L10,0L0,5");

svg.append("defs").selectAll("marker")
.data(["concomidant"])
.enter().append("marker")
.attr("id", function (d) {
return d;
})
.attr("viewBox", "0 -5 10 10")
.attr("refX", 15)
.attr("refY", -1.5)
.attr("markerWidth", 12)
.attr("markerHeight", 12)
.attr("orient", "auto-start-reverse")
.append("path")
.attr("d", "M0,-5L10,0L0,5");

var path = svg.append("g").selectAll("path")
.data(force.links())
.enter().append("path")
.attr("class", function (d) {
return "link " + d.type;
})
.attr("marker-end", function (d) {
return "url(#" + d.type + ")";
})
.attr("marker-start", function (d) {
if (d.type == "concomidant") {
return "url(#" + d.type + ")";
}
});


var circle = svg.append("g").selectAll("circle")
.data(force.nodes())
.enter().append("circle")
.attr("r", function (d) {
return d.weight * 4;
})
.call(force.drag);

var text = svg.append("g").selectAll("text")
.data(force.nodes())
.enter().append("text")
.attr("x", 8)
.attr("y", ".31em")
.text(function (d) {
return d.name;
});

// Use elliptical arc path segments to doubly-encode directionality.
function tick() {
path.attr("d", linkArc);
circle.attr("transform", transform);
text.attr("transform", transform);
}

function linkArc(d) {
var dx = d.target.x - d.source.x,
dy = d.target.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);

return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + d.target.x + "," + d.target.y;
}

function transform(d) {
return "translate(" + d.x + "," + d.y + ")";
}

它可以为不同的链接添加不同类型的标记,但如果节点变大(根据它们的权重),标记会被节点覆盖。

这是现在的截图:

D3 Force Graph

有没有办法将我的标记准确定位在节点的边缘?

最佳答案

有趣的问题。这通过正常设置链接路径,然后通过将长度退回圆的半径来重新计算结束位置来实现。

首先在标记 def 中,将 refXrefY 设置为 0(这是当前它保持在圆圈外的方式):

  .attr("refX", 0)
.attr("refY", 0)

然后做:

function tick() {

// fit path like you've been doing
path.attr("d", function(d){
var dx = d.target.x - d.source.x,
dy = d.target.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);
return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + d.target.x + "," + d.target.y;
});

// recalculate and back off the distance
path.attr("d", function(d) {

// length of current path
var pl = this.getTotalLength(),
// radius of circle plus marker head
r = (d.target.weight) * 4 + 16.97, //16.97 is the "size" of the marker Math.sqrt(12**2 + 12 **2)
// position close to where path intercepts circle
m = this.getPointAtLength(pl - r);

var dx = m.x - d.source.x,
dy = m.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);

return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + m.x + "," + m.y;
});

circle.attr("transform", transform);
text.attr("transform", transform);
}

运行代码:

<!DOCTYPE html>
<html>

<head>
<script data-require="d3@3.5.17" data-semver="3.5.17" src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.17/d3.js"></script>
<style>
path.link {
fill: none;
stroke: #666;
stroke-width: 1.5px;
}

circle {
fill: #ccc;
stroke: #fff;
stroke-width: 1.5px;
}

text {
fill: #000;
font: 10px sans-serif;
pointer-events: none;
}
</style>
</head>

<body>
<script>
var links = [{
"source": "Harry",
"target": "Sally",
"value": "1.2"
}, {
"source": "Harry",
"target": "Mario",
"value": "1.3"
}, {
"source": "Sarah",
"target": "Alice",
"value": "0.2"
}, {
"source": "Eveie",
"target": "Alice",
"value": "0.5"
}, {
"source": "Peter",
"target": "Alice",
"value": "1.6"
}, {
"source": "Mario",
"target": "Alice",
"value": "0.4"
}, {
"source": "James",
"target": "Alice",
"value": "0.6"
}, {
"source": "Harry",
"target": "Carol",
"value": "0.7"
}, {
"source": "Harry",
"target": "Nicky",
"value": "0.8"
}, {
"source": "Bobby",
"target": "Frank",
"value": "0.8"
}, {
"source": "Alice",
"target": "Mario",
"value": "0.7"
}, {
"source": "Harry",
"target": "Alice",
"value": "0.5"
}, {
"source": "Sarah",
"target": "Alice",
"value": "1.9"
}, {
"source": "Roger",
"target": "Alice",
"value": "1.1"
}];

var nodes = {};

// Compute the distinct nodes from the links.
links.forEach(function(link) {
link.type = "dominating";
link.source = nodes[link.source] || (nodes[link.source] = {
name: link.source
});
link.target = nodes[link.target] || (nodes[link.target] = {
name: link.target
});
});

var width = 500,
height = 500;

var force = d3.layout.force()
.nodes(d3.values(nodes))
.links(links)
.size([width, height])
.linkDistance(300)
.charge(-120)
.friction(0.9)
.on("tick", tick)
.start();

var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);

// Per-type markers, as they don't inherit styles.
svg.append("defs").selectAll("marker")
.data(["dominating"])
.enter().append("marker")
.attr("id", function(d) {
return d;
})
.attr("viewBox", "0 -5 10 10")
.attr("refX", 0)
.attr("refY", 0)
.attr("markerWidth", 12)
.attr("markerHeight", 12)
.attr("orient", "auto")
.append("path")
.attr("d", "M0,-5L10,0L0,5");

svg.append("defs").selectAll("marker")
.data(["concomidant"])
.enter().append("marker")
.attr("id", function(d) {
return d;
})
.attr("viewBox", "0 -5 10 10")
.attr("refX", 0)
.attr("refY", 0)
.attr("markerWidth", 12)
.attr("markerHeight", 12)
.attr("orient", "auto-start-reverse")
.append("path")
.attr("d", "M0,-5L10,0L0,5");

var path = svg.append("g").selectAll("path")
.data(force.links())
.enter().append("path")
.attr("class", function(d) {
return "link " + d.type;
})
.attr("marker-end", function(d) {
return "url(#" + d.type + ")";
})
.attr("marker-start", function(d) {
if (d.type == "concomidant") {
return "url(#" + d.type + ")";
}
});


var circle = svg.append("g").selectAll("circle")
.data(force.nodes())
.enter().append("circle")
.attr("r", function(d) {
return d.weight * 4;
})
.call(force.drag);

var text = svg.append("g").selectAll("text")
.data(force.nodes())
.enter().append("text")
.attr("x", 8)
.attr("y", ".31em")
.text(function(d) {
return d.name;
});

function tick() {
path.attr("d", function(d){
var dx = d.target.x - d.source.x,
dy = d.target.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);
return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + d.target.x + "," + d.target.y;
});
path.attr("d", function(d) {
var pl = this.getTotalLength(),
r = (d.target.weight) * 4 + 16.97, //16.97 is the "size" of the marker Math.sqrt(12**2 + 12 **2)
m = this.getPointAtLength(pl - r);

var dx = m.x - d.source.x,
dy = m.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);

return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + m.x + "," + m.y;
});
circle.attr("transform", transform);
text.attr("transform", transform);
}


function transform(d) {
return "translate(" + d.x + "," + d.y + ")";
}
</script>
</body>

</html>

关于javascript - 在节点边缘对齐标记 D3 强制布局,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41226734/

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