Javascript findIndex 不是函数

Question

我有一个 json 数组:

[    
  {"id":19,"name":"Jed", "lastname":"DIAZ", "hobby":"photo", "birthday":"2011/11/22"},
  {"id":20,"name":"Judith", "lastname":"HENDERSON", "hobby":"pets", "birthday":"1974/06/12"},
  {"id":21,"name":"Nicolai", "lastname":"GRAHAM", "hobby":"reading", "birthday":"2005/01/22"},
  {"id":22,"name":"Vasile", "lastname":"BRYANT", "hobby":"singing", "birthday":"1987/03/17"}
]

从 json 数组中删除一个项目的函数

 removeItem: function(removeId){
   //paramater validation
   return dataLoad.then(function(data){

     f = data.findIndex(function(item) { return item.id == removeId; });

     if(f < 0)
       return false;
     data.splice(f,1);

     LS.setData(data,"cutomers");

     return true;
   });
 }

代码运行时出现错误:

findIndex is not a function

错误行

 f = data.findIndex(function(item) { return item.id == removeId; });

Answer 1

findIndex 不是 ECMASCRIPT 262 中 Array 的原型(prototype)方法，您可能需要 filter 与 indexOf 结合使用，相反，它的优点是一旦找到条目就停止搜索

var f;
var filteredElements = data.filter(function(item, index) { f = index; return item.id == removeId; });


if (!filteredElements.length) {
    return false;
}

data.splice(f, 1);

---

按照 Nina Scholz 评论中的建议进行编辑:

此解决方案使用 Array.prototype.some相反

var f;
var found = data.some(function(item, index) { f = index; return item.id == removeId; });

if (!found) {
    return false;
}

data.splice(f, 1);

---

发现于 Array.prototype.findIndex MDN