javascript - Node.js 作为 JSON 转发器

Question

我是 Node.js 的新手，但我想将它用作一个快速的 Web 服务器，它只需接收请求 uri，然后在返回 JSON 流的内部服务上运行查询。

即像这样:

http.createServer(function(request, response) {
  var uri = url.parse(request.url).pathname;
  if(uri === "/streamA") {
    //send get request to internal network server http://server:1234/db?someReqA -->Returns JSON ....?
    //send response to requestor of the JSON from the above get ....?
  }
  else if(uri === "/streamB") {
    //send get request to internal network server http://server:1234/db?someReqB -->Returns JSON ....?
    //send response to requestor of the JSON from the above get....?
}.listen(8080);

我使用的是最新的稳定版 node.js - 版本 0.4.12。我希望这会很容易做到，但是，我无法在网上找到一些示例，因为它们似乎都使用旧的 API 版本，所以我一个接一个地收到错误。

是否有人能够提供适用于新 Node API 的上述代码解决方案？

谢谢!

Answer 1

这里有一段代码可以解释你的任务:

var http = require('http');
var url = require('url')

var options = {
  host: 'www.google.com',
  port: 80,
  path: '/' //Make sure path is escaped
}; //Options for getting the remote page

http.createServer(function(request, response) {
  var uri = url.parse(request.url).pathname;
  if(uri === "/streamA") {
    http.get(options, function(res) {

        res.pipe( response ); //Everything from the remote page is written into the response
        //The connection is also auto closed

    }).on('error', function(e) {
        response.writeHead( 500 ); //Internal server error
        response.end( "Got error " + e); //End the request with this message
    });

  } else {
    response.writeHead( 404 ); //Could not find it
    response.end("Invalid request");

  }

}).listen(8080);