gpt4 book ai didi

javascript - D3.js:折线图 - 工具提示和悬停垂直线

转载 作者:数据小太阳 更新时间:2023-10-29 04:14:28 25 4
gpt4 key购买 nike

我一直在研究使用 D3.js 构建的交互式折线图。悬停一次我希望工具提示显示为一条垂直线。垂直线很好,但是,我遇到了与工具提示相关的问题。工具提示位置不在图表上,我只得到第一个数据元素。

这是我的代码:

 margin = {
top: 20,
right: 20,
bottom: 20,
left: 50
};
var width = Math.max(250, Math.min(700, d3.select("#content").width- margin.left - margin.right)),
height = 500;

var vis = d3.select("#line_chart").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom);

max_x = 0, max_y = 0, min = 100;

d3.csv("line.csv", function(error, data) {


for(i=0; i < data.length; i++){
max_y = Math.max(max_y, data[i].number);
max_x = Math.max(max_x, data[i].class);
min = Math.min(min, data[i].class);
}


xScale = d3.scale.linear().range([margin.left, width - margin.right]).domain([min, max_x]),

yScale = d3.scale.linear().range([height - margin.top, margin.bottom]).domain([0, max_y]),

xAxis = d3.svg.axis()
.scale(xScale),

yAxis = d3.svg.axis()
.scale(yScale)
.orient("left");

vis.append("svg:g")
.attr("class", "x axis")
.attr("transform", "translate(0," + (height - margin.bottom) + ")")
.call(xAxis);

vis.append("svg:g")
.attr("class", "y axis")
.attr("transform", "translate(" + (margin.left) + ",0)")
.call(yAxis);

var lineGen = d3.svg.line()
.x(function(d) {
return xScale(d.class);
})
.y(function(d) {
return yScale(d.number);
})
.interpolate("basis");

var pth = vis.append('svg:path')
.attr('d', lineGen(data))
.attr('stroke', '#000')
.attr('stroke-width', 3.5)
.attr('fill', 'none');

var totalLength = pth.node().getTotalLength();

pth
.attr("stroke-dasharray", totalLength + " " + totalLength)
.attr("stroke-dashoffset", totalLength)
.transition()
.duration(2400)
.ease("linear")
.attr("stroke-dashoffset", 0);

//Line chart mouse over
var hoverLineGroup = vis.append("g")
.attr("class", "hover-line");

var hoverLine = hoverLineGroup
.append("line")
.attr("stroke", "#000")
.attr("x1", 10).attr("x2", 10)
.attr("y1", 0).attr("y2", height);

var hoverTT = hoverLineGroup.append('text')
.attr("class", "hover-tex capo")
.attr('dy', "0.35em");

var cle = hoverLineGroup.append("circle")
.attr("r", 4.5);

var hoverTT2 = hoverLineGroup.append('text')

.attr("class", "hover-text capo")
.attr('dy', "0.35em");

hoverLineGroup.style("opacity", 1e-6);

var rectHover = vis.append("rect")
.data(data)
.attr("class", "overlay")
.attr("width", width)
.attr("height", height);

rectHover
.on("mouseout", hoverMouseOff)
.on("mousemove", hoverMouseOn);

function hoverMouseOn(d) {

var mouse_x = d3.mouse(this)[0];
var mouse_y = d3.mouse(this)[1];
var graph_y = yScale.invert(mouse_y);
var graph_x = xScale.invert(mouse_x);

hoverTT.text("Marks: " + Math.round(graph_x * 100)/100);
hoverTT.attr('x', mouse_x + 10);
hoverTT.attr('y', yScale(d.class));


hoverTT2.text("Frequency: " + Math.round(d.number * 100)/100)
.attr('x', mouse_x + 10)
.attr('y', yScale(d.class) +15);

cle
.attr('x', mouse_x)
.attr('y', mouse_y);


hoverLine.attr("x1", mouse_x).attr("x2", mouse_x)
hoverLineGroup.style("opacity", 1);

}

function hoverMouseOff() {
hoverLineGroup.style("opacity", 1e-6);
};

});
}

数据:

class,number
25,1
30,7
35,11
45,13
50,21
55,23
60,30
65,41
75,39
80,24
85,14
90,4
95,8
100,2

我无法弄清楚问题是什么。

我该如何解决这个问题?

提前致谢。

编辑:这是工作代码:https://jsfiddle.net/kan83q0m/1/

最佳答案

在您的 hoverMouseOn 方法中,变量 d 未定义。您需要使用 d3.bisector 来查找最近的数据点,如下所示:

var bisectDate = d3.bisector(function(d) { return d.class; }).left;

var mouseDate = xScale.invert(mouse_x);
var i = bisectDate(data, mouseDate);

var d0 = data[i - 1]
var d1 = data[i];
var d = mouseDate - d0[0] > d1[0] - mouseDate ? d1 : d0;

此外,我将 mousemove 监听器放在“vis”而不是“rectHover”上:

        vis  
.on("mouseout", hoverMouseOff)
.on("mousemove", hoverMouseOn);

并使用 d.number 而不是 d.class 作为 y 值。如果您希望工具提示始终在线,请 gets a bit more complicated . Here's a working fiddle.

将工具提示放在鼠标坐标处可能会更容易 like in this fiddle.

关于javascript - D3.js:折线图 - 工具提示和悬停垂直线,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42433779/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com