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javascript - Selenium:滚动到页面末尾

转载 作者:数据小太阳 更新时间:2023-10-29 04:13:30 28 4
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Selenium :

我是 WebDriverJS 的新手.我已经在 J​​ava 中尝试过这种方法。

Long repaeted = 0l, scrollHeight = 0l, returnHeight = 0l;
while(true){
if (repaeted == 0) {
returnHeight = (Long) jse.executeScript("var scroll =document.documentElement.scrollHeight;window.scrollTo(0, scroll); return scroll;");
System.out.println("Height : "+scrollHeight +"\t Chnage : "+returnHeight+ "\t Repeated : "+repaeted);
scrollHeight = returnHeight;
}else {
returnHeight = (Long) jse.executeScript("var scroll = document.documentElement.scrollHeight;window.scrollTo(0, scroll); return scroll;");
System.out.println("Height : "+scrollHeight +"\t Chnage : "+returnHeight+ "\t Repeated : "+repaeted);
if (scrollHeight.intValue() == returnHeight.intValue()) {
System.out.println("Break.."+ returnHeight);
break;
} else { scrollHeight = returnHeight; }
}
repaeted++;
}

但我在迭代循环时遇到 webdriverjs 中的问题。

var webdriver = require('..'),
By = webdriver.By,
until = webdriver.until;
// make sure chromedriver can be found on your system PATH
var driver = new webdriver.Builder()
.forBrowser('chrome')
.withCapabilities(webdriver.Capabilities.chrome())
.build();


driver.get('https://in.yahoo.com/').then(function(){
var window = new webdriver.WebDriver.Window(driver);
window.maximize();
driver.manage().timeouts().implicitlyWait(1000 * 3);
})
.then(function(){
console.log('Entered');
var check = 0, count = 0
for(var i = 0; i< 50; i++){
//driver.sleep(1000 * 2);
driver.executeScript('var dynamicscroll = document.documentElement.scrollHeight;window.scrollTo(0, dynamicscroll);return dynamicscroll;').then(function(height){
console.log('Check : '+check+' Height : '+height +' Repeated : '+(count++));
if(check === 0 || check !== height){console.log('continue'); check = height; }
else { console.log('break'); i = 100; }
});
}
})
.then(null, function(err) {
console.error("An error was thrown! By Promise..." + err);
});

driver.quit();

在我的代码中,我已经将循环硬编码为迭代 50 次,并且我想在滚动高度达到结束时退出/中断循环。在这种方法中,我想删除像 java 代码这样的硬代码,因为我不知道要为滚动保持动态增加的其他应用程序迭代多少次。例如,Facebook 应用程序、雅虎新闻...

最佳答案

滚动到动态页面的底部可能具有挑战性,具体取决于页面的实现方式。

首先,您必须找到带有滚动条的容器,因为它可能与链接到 window.scrollTo 的容器不同。

然后通过增加 scrollTop 滚动容器,直到 scrollHeight 变得稳定且没有待处理的请求。要检查是否有待处理的请求,请评估 jQuery.active 页面是否有 JQuery 或 Hook XMLHttpRequest 以监视对 send 的调用。

下面是一个使用通用函数多次滚动到页面底部或直到结束的示例:

var webdriver = require('selenium-webdriver');

var driver = new webdriver.Builder().forBrowser('chrome').build();

driver.get('https://groups.google.com/forum/#!search/webdriverjs');

// scroll to the bottom 3 times
driver.executeAsyncScript(scrollBottom, 3)
.then(n => console.log(`scrolled ${n} time(s)`));

// scroll to the bottom until the end
driver.executeAsyncScript(scrollBottom)
.then(n => console.log(`scrolled ${n} time(s)`));
function scrollBottom(){
var count = arguments[arguments.length - 2] || 0x7fffffff;
var callback = arguments[arguments.length - 1];

/* get the scrollable container */
var elm = document.elementFromPoint(window.innerWidth - 25, window.innerHeight / 2);
for ( ;elm && (++elm.scrollTop, !elm.scrollTop); elm=elm.parentElement);
elm = elm || document.documentElement;

/* hook XMLHttpRequest to monitor Ajax requests */
if (!('idle' in XMLHttpRequest)) (function(){
var n = 0, t = Date.now(), send = XMLHttpRequest.prototype.send;
var dispose = function(){ --n; t = Date.now(); };
var loadend = function(){ setTimeout(dispose, 1) };
XMLHttpRequest.idle = function() { return n > 0 ? 0 : Date.now() - t; };
XMLHttpRequest.prototype.send = function(){
++n;
this.addEventListener('loadend', loadend);
send.apply(this, arguments);
};
})();

/* scroll until steady scrollHeight or count of scroll and no pending request */
var i = 0, scrollHeight = -1, scrollTop = -1;
(function scroll(){
if ((scrollHeight === elm.scrollHeight || i === count) && XMLHttpRequest.idle() > 60)
return callback(i);
scrollTop = elm.scrollTop;
scrollHeight = elm.scrollHeight;
if (i < count)
i += (elm.scrollTop = 0x7fffffff, scrollTop !== elm.scrollTop);
setTimeout(scroll, 100);
})();
}

或者通过滚动直到高度在特定时间内不再增加(此处为 5 秒):

function scrollBottom(){
var count = arguments[arguments.length - 2] || 0x7fffffff;
var callback = arguments[arguments.length - 1];
var timeout = 5000; /* 5 seconds timeout */
var i = 0;

/* get the scrollable container */
var elm = document.elementFromPoint(window.innerWidth - 25, window.innerHeight / 2);
for ( ;elm && (++elm.scrollTop, !elm.scrollTop); elm=elm.parentElement);
elm = elm || document.documentElement;

/* scroll while the height is increasing or until timeout */
(function scroll(){
var endtime = Date.now() + timeout;
var height = elm.scrollHeight;
elm.scrollTop = 0x7fffffff; /* scroll */

setTimeout(function check(){
if (Date.now() > endtime) /* returns if waited more than 5 sec */
callback(i);
else if (elm.scrollHeight == height) /* wait again if same height */
setTimeout(check, 60);
else if (++i === count) /* returns if scrolled the expected count */
callback(i);
else /* scroll again */
setTimeout(scroll, 60);
}, 250);
})();
}

关于javascript - Selenium:滚动到页面末尾,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33094727/

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