javascript - 在使用 `Math.random()` 时，我是否应该考虑 2^62 中有 1 种可能性获得排除的上限？

Question

来自 MDN(https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Math/random):

Math.random

Returns a floating-point, pseudo-random number in the range [0, 1) that is, from 0 (inclusive) up to but not including 1 (exclusive), which you can then scale to your desired range.

但是，它说:

Note that as numbers in JavaScript are IEEE 754 floating point numbers with round-to-nearest-even behavior, these ranges, excluding the one for Math.random() itself, aren't exact, and depending on the bounds it's possible in extremely rare cases (on the order of 1 in 2^62) to calculate the usually-excluded upper bound.

我应该考虑这些情况吗？例如，使用...

Math.min(max, Math.floor(Math.random() * (max - min + 1)) + min);

...而不是...

Math.floor(Math.random() * (max - min + 1)) + min;

...?

Answer 1

如果您每秒调用 Math.random() 十亿 次，您应该预计每 150 年左右就会遇到此错误。我对 Javascript 方式 的性能评价过高。 :-)