go - 我想在 goroutines 之间通信并无限期地阻塞主线程

Question

我如何阻止 main func 并允许 goroutines 通过 channel 进行通信以下代码示例会抛出错误

0 fatal error :所有 goroutines 都睡着了 - 死锁!

package main

import (
  "fmt"
  "time"
)

func main() {
   ch := make(chan int)

   go func() {
       value := <-ch
       fmt.Print(value) // This never prints!
   }()

   go func() {
       for i := 0; i < 100; i++ {
           time.Sleep(100 * time.Millisecond)
           ch <- i
       }
   }()

   c := make(chan int)
   <-c
}

Answer 1

我想你想打印所有值 [0:99]。然后你需要在第一个 go routine 中循环。

另外，你需要传递信号来打破循环

func main() {
    ch := make(chan int)
    stopProgram := make(chan bool)

    go func() {
        for i := 0; i < 100; i++ {
            value := <-ch
            fmt.Println(value)
        }
        // Send signal through stopProgram to stop loop
        stopProgram <- true
    }()

    go func() {
        for i := 0; i < 100; i++ {
            time.Sleep(100 * time.Millisecond)
            ch <- i
        }
    }()

    // your problem will wait here until it get stop signal through channel
    <-stopProgram
}