go - 通过范围函数中的地址引用

Question

我有一个定义如下的 OuterStruct 结构。我正在使用该函数初始化 OuterStruct -> InnerStruct 值 name 和 Var1 in setup1() 和 Var1在 setup2() 中。

在 setup2() 中分配的值总是 nil 因为它是按值引用它的。如何使用在这里引用我的地址？

type InnerStruct struct {
    Name  string
    Var1  *api.Var1
    Var2  *ap1.Var2
}

type OuterStruct struct {
    opName   string
    MyData   []InnerStruct
    LogDir   string
}

func (obj *OuterStruct) Setup2() {
    for _, innerObj := range obj.InnerStruct {   // Here is the prob becuase of using refer by value
        innerObj.Var2 = callToPopulateValue()
    }
}

func Setup1() {
    innerStructList := []InnerStruct

    myStruct := InnerStruct{}
    myStruct.Name = "name1"
    myStruct.Var1 = callToPopulateValue()
    innerStructList = append(innerStructList, myStruct)

    finalStruct = &OuterStruct {
        opName: "structName",
        MyData: innerStructList,
        LogDir: "/path/for/my/logs",
    }

    finalStruct.Setup2()
}

Answer 1

你不能通过地址访问，但你可以从 range 中获取索引，并直接分配给 slice :

    for i := range obj.MyData {
        obj.MyData[i].Var2 = callToPopulateValue()
    }

或者，您可以只使用一片指针值:

type OuterStruct struct {
    opName   string
    MyDAta   []*InnerStruct
    LogDir   string
}

func (obj *OuterStruct) Setup2() {
    for _, innerObj := range obj.MyData {
        innerObj.Var2 = callToPopulateValue()
    }
}