pointers - 指向结构的指针更改未反射(reflect)在调用者中

Question

我将一个指向结构的指针传递给另一个名为someFunc()的函数并在那里进行更改，但在本例中，它不会反映在调用方函数中。

type Slot struct {
  f1 int
  f2 string
  f3 []*string
}

func NewSlot(f1, f2){
  return &Slot{f1: f1, f2: f2, f2: make([]*string, 0)}
}

func main() {

  slots := &Slots{}
  scanner := bufio.NewScanner(os.Stdin)
  for scanner.Scan() {
    s := scanner.Text()
    sarr := strings.Split(s, " ")
    fmt.Println("scanner", slots)
    someFunc(slots, sarr[0], sarr[1:]...)
  }
 }
func someFunc(slots *Slots, cmd string, args ...string) {
  slots = NewSlots(5) // return Pointer to slots with 5 and other value initialized

  // But not reflecting to main() func, Why?
}

Answer 1

我在“阿德里安”的帮助下找到了这个。这就是它的工作原理。

func main() {

  slots := &Slots{}
  scanner := bufio.NewScanner(os.Stdin)
  for scanner.Scan() {
    s := scanner.Text()
    sarr := strings.Split(s, " ")
    fmt.Println("scanner", slots)
    someFunc(&slots, sarr[0], sarr[1:]...)
  }
 }
func someFunc(slotsPtr **Slots, cmd string, args ...string) {
  *slotsPtr = NewSlots(5) // return Pointer to slots with 5 and other value initialized

  // and used *slotsPtr in rest of the program
}