xml - 从结构编码 xml

Question

我刚开始尝试让下面的代码正常工作，但运气不好。看起来我没有正确编码结构部分的结构。帮助!

package main

import (
    "encoding/xml"
    "fmt"
    "os"
)

func main() {

    type Person struct {
        Email string `xml:"email"`
        Phone string `xml:"phone"`
    }

    type Host struct {
        Hostname string `xml:"hostname"`
        Address  string `xml:"address"`
    }

    type Asset struct {
        person Person
        host   Host
    }

    p := &Person{Email: "person@a.com", Phone: "1111"}
    h := &Host{Hostname: "boxen", Address: "1 Place St"}
    a := &Asset{person: *p, host: *h}

    enc := xml.NewEncoder(os.Stdout)
    enc.Indent(" ", " ")
    if err := enc.Encode(p); err != nil {
        fmt.Printf("error: %v\n", err)
    }
    if err := enc.Encode(h); err != nil {
        fmt.Printf("error: %v\n", err)
    }
    if err := enc.Encode(a); err != nil {
        fmt.Printf("error: %v\n", err)
    }
}

Go playground here

预期输出。我目前得到的是一个空的 Asset 元素。

 <Asset>
   <Person>
    <email>person@a.com</email>
    <phone>1111</phone>
   </Person>
   <Host>
    <hostname>boxen</hostname>
    <address>1 Place St</address>
   </Host>
 </Asset>

Answer 1

只要 person 和 host 未导出，enc.Encode 就无法知道它们。导出它们将提供您想要的输出。

package main

import (
    "encoding/xml"
    "fmt"
    "os"
)

func main() {

    type Person struct {
        Email string `xml:"email"`
        Phone string `xml:"phone"`
    }

    type Host struct {
        Hostname string `xml:"hostname"`
        Address  string `xml:"address"`
    }

    type Asset struct {
        Person Person
        Host   Host
    }

    p := &Person{Email: "person@a.com", Phone: "1111"}
    h := &Host{Hostname: "boxen", Address: "1 Place St"}
    a := &Asset{Person: *p, Host: *h}

    enc := xml.NewEncoder(os.Stdout)
    enc.Indent(" ", " ")

    if err := enc.Encode(a); err != nil {
        fmt.Printf("error: %v\n", err)
    }
}