戈朗 : How to run the same logic at the beginning of every struct member functions?

Question

例如，我想打印出某个结构的每个函数的函数名。

除了我在每个成员函数的开头使用fmt.Println，还有什么更好的方法吗？

Answer 1

package main

import "fmt"
import "runtime"

func main() {
    pc, _, _, _ := runtime.Caller(0)
    fmt.Println("Name of function: " + runtime.FuncForPC(pc).Name())
    fmt.Println()

    // or, define a function for it
    fmt.Println("Name of function: " + funcName())
    x()
}

func funcName() string {
    pc, _, _, _ := runtime.Caller(1)
    return runtime.FuncForPC(pc).Name()
}

func x() {
    fmt.Println("Name of function: " + funcName())
    y()
}

func y() {
    fmt.Println("Name of function: " + funcName())
    z()
}
func z() {
    fmt.Println("Name of function: " + funcName())
}

Output:

Name of function: main.main

Name of function: main.main
Name of function: main.x
Name of function: main.y
Name of function: main.z

(从 here 复制)