go - 如何获取指针的地址？

Question

package main

import "fmt"

func main() {
   var a int= 20   
   var ip *int    

   ip = &a 

   fmt.Printf("a address: %x\n", &a  )

   fmt.Printf(" the adrress that ip stored: %x\n", ip )
   /*I try to get the address of variable ip */
   fmt.Printf(" the address of ip: %d\n", &ip )

}

go run a.go

结果:

地址:c420016078ip存储的地址:c420016078 ip地址:842350510120

我的问题是:842350510120是正确的ip地址吗？

Answer 1

如果您以一致的基数(十六进制)打印地址，您将看到预期的结果。在当前版本的 Go gc 编译器中，变量 i 和 pi 分配在堆上。

例如，

package main

import "fmt"

func main() {
    var i int = 20
    var pi *int = &i
    fmt.Printf("%x the address of i\n", &i)
    fmt.Printf("%x the address of pi\n", &pi)
    fmt.Printf("%x the address that pi stored\n", pi)
}

输出:

c00008e010 the address of i
c000090018 the address of pi
c00008e010 the address that pi stored