go - 将变量传递给结构函数

Question

type MultiplyStruct struct {
    Number1 int
}

func (m MultiplyStruct) Multiply() int {
    return m.Number1 * number2
}

如何将 number2 传递给 Multiply 函数？会是这样吗？

   var multiplier = MultiplyStruct(10)
   multiplier.Multiply(20)

Answer 1

我认为这就是您想要的:

package main

import (
    "fmt"
)

type MultiplyStruct struct {
    Number1 int
}

func (m MultiplyStruct) Multiply(number2 int) int {
    return m.Number1 * number2
}

func main() {
    multipler := MultiplyStruct{Number1: 10}
    val := multipler.Multiply(20)
    fmt.Println(val)
}

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