pointers - Golang 中 []*Users 和 *[]Users 的区别？

Question

虽然我不得不将一些数据指向结构，但我对 Golang 结构中 []*Users 和 *[]Users 之间的区别感到困惑

我有以下结构

type Users struct {
    ID int
    Name string
}

Answer 1

区别还是挺大的:

*[]Users 将是指向 Users slice 的指针。例如:

package main

import (
    "fmt"
)

type Users struct {
    ID int
    Name string
}

var (
    userList []Users
)

func main(){
    //Make the slice of Users
    userList = []Users{Users{ID: 43215, Name: "Billy"}}

    //Then pass the slice as a reference to some function
    myFunc(&userList);

    fmt.Println(userList) // Outputs: [{1337 Bobby}]
}


//Now the function gets a pointer *[]Users that when changed, will affect the global variable "userList"
func myFunc(input *[]Users){
    *input = []Users{Users{ID: 1337, Name: "Bobby"}}
}

相反，[]*Users 将是指向Users 的指针片段。例如:

package main

import (
    "fmt"
)

type Users struct {
    ID int
    Name string
}

var (
    user1 Users
    user2 Users
)

func main(){
    //Make a couple Users:
    user1 = Users{ID: 43215, Name: "Billy"}
    user2 = Users{ID: 84632, Name: "Bobby"}

    //Then make a list of pointers to those Users:
    var userList []*Users = []*Users{&user1, &user2}

    //Now you can change an individual Users in that list.
    //This changes the variable user2:
    *userList[1] = Users{ID:1337, Name: "Larry"}

    fmt.Println(user1) // Outputs: {43215 Billy}
    fmt.Println(user2) // Outputs: {1337 Larry}
}

两者都使用指针，但方式完全不同。在 Golang Playground 上自行处理这两个片段并通读this以获得更好的理解。