go - 将包含字符串的 []byte 转换为十进制值

Question

我正在尝试获取一个字符串并将字符串中的每个值转换为十进制 ASCII 值。我首先将字符串转换为 []byte 类型，我想获取 []byte 的每个元素并将其转换为十进制 ASCII 值。这是我的代码:

myArray := []byte(password) // convert string into []byte type
NumArray := [len(password)]int // create second []int type to store the    converted []byte elements
for i := 0; i < len(myArray); i++{
                                /*  I need some help to convert each element in myArray into ASCII decimal value and then store it into 
                                    NumArray.
                                */
fmt.Printf("%d\n", myArray[i]) //prints out what the converted values should be
fmt.Print(NumArray[i]) //prints out the stored converted value for comparison
}

编辑:该字符串应该是密码，因此可以包含任何值

Answer 1

你可以像这样将 byte 转换为 int:

NumArray[i] = int(myArray[i])