go - 将 web api 暴露给使用 Golang 接受 json 和/或参数的第三方

Question

我最近开始学习 GoLang。我的目标是公开一个 webapi。这应该能够接受一个 json 对象并且应该用另一个 json 对象响应。我没有找到足够的资源来学习如何让它工作。我真的很感谢在这方面的任何帮助。我的一段代码如下所示。

func HelloService(res http.ResponseWriter, req *http.Request){
io.WriteString(res,"Welcome to service")
}

func main(){
    http.HandleFunc("/", HelloService)
    http.ListenAndServe(":8080",nil)
    http.HandleFunc("/saveuser", saveUser)
}

func saveUser(res http.ResponseWriter, req *http.Request){
    ConfigurationRepository.SaveUser(User) //I want to receive an User    object when this service is being consumed
}

Answer 1

包装“net/http”的http 包会很有帮助。示例:

https://github.com/emicklei/go-restful

https://github.com/gin-gonic/gin

这是一个帮助您入门的简单服务:

package main

import (
    "github.com/emicklei/go-restful"
    "log"
    "net/http"
)

type User struct {
    Name string
}

func postOne(req *restful.Request, resp *restful.Response) {
    newUser := new(User)
    err := req.ReadEntity(newUser)
    if err != nil {
        resp.WriteErrorString(http.StatusBadRequest, err.Error())
        return
    }

    log.Printf("new user: '%v'", newUser)
}

func main() {
    ws := new(restful.WebService)
    ws.Path("/users")
    ws.Consumes(restful.MIME_JSON)
    ws.Produces(restful.MIME_JSON)

    ws.Route(ws.POST("").To(postOne).
        Param(ws.BodyParameter("User", "A User").DataType("main.User")))

   restful.Add(ws)

  http.ListenAndServe(":8080", nil)
}

这是一个通过发布单个用户来测试服务的 curl:

curl -v -H "Content-Type: application/json" -XPOST "localhost:8080/users" -d '{"name": "Joe"}'