go - http.NewRequest() 解码我的 URL 输入

Question

当使用 http.NewRequest("GET", url , nil) 用于包含 % 后跟某个数字的 URL 时，*示例:https://api.deutschebahn.com/freeplan/v1/journeyDetails/356418%252F128592%252F57070%252F90271%252F80%253fstation_evaId%253D8000261) Go 会将字符串编码为 url 中的“/”。我怎样才能避免这种情况？

Answer 1

显式设置 URL 结构的 RawPath 字段:

req := http.NewRequest("GET", "https://api.deutschebahn.com/freeplan/v1/journeyDetails/356418%252F128592%252F57070%252F90271%252F80%253fstation_evaId%253D8000261", nil)
req.URL.RawPath = "/freeplan/v1/journeyDetails/356418%252F128592%252F57070%252F90271%252F80%253fstation_evaId%253D8000261"

这个功能是documented对于这个用例:

Note that the Path field is stored in decoded form: /%47%6f%2f becomes /Go/. A consequence is that it is impossible to tell which slashes in the Path were slashes in the raw URL and which were %2f. This distinction is rarely important, but when it is, code must not use Path directly.

Go 1.5 introduced the RawPath field to hold the encoded form of Path. The Parse function sets both Path and RawPath in the URL it returns, and URL's String method uses RawPath if it is a valid encoding of Path, by calling the EscapedPath method.