php - 遍历数组 PHP

Question

我正在尝试循环访问 cURL 数组响应以生成 XML 文件。但是，我生成的文件似乎都具有完全相同的内容——我不知道这是否是正确的方法，或者我是否应该使用数组，但我似乎无法弄清楚，可以使用一些新的眼睛.基本上，我希望每个 $playlist 的内容都在其自己的单独文件中。

for ($i=0; $i<=14; $i++) {
    $xml_data = generateXML($i);
    $fileName = "bc_manifest_$i.xml";
    $fileHandle = fopen($fileName, 'wb') or die("can't open file");
    fwrite ($fileHandle, $xml_data);
    fclose($fileHandle);
    //echo $xml_data;
    echo "Successfully created manifest $i<br />";
  }

// The holy grail
function generateXML($i) {
    $xml_code = array($i);
    // Start the beginning of the xml doc and save it to our reoccuring xml_code var
    $xml_code[$i] .= '<?xml version="1.0" encoding="UTF-8"?>' . "\n";
    $xml_code[$i] .= '<publisher-upload-manifest publisher-id="xxxxxxx" preparer="Dave" report-success="TRUE">' . "\n";

    // Set options to send to brightcove
    // @page_size
    $options = array(
                'page_size' => '75',
                'playlist_ids' => "3690598001,3684920001,8193433701",
                'video_fields'     => 'referenceId,creationDate'    
    );

    // URL Encode the options to prepare for cURL send
    $post_str = '';
    foreach($options as $key=>$value) {
        $post_str .= $key.'='.urlencode($value).'&';
    }
    $post_str = substr($post_str, 0, -1);

    // Initiate cURL and send request
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, 'http://api.brightcove.com/services/library?command=find_playlists_by_ids&token=xxxxxxxxxx&' );
    curl_setopt($ch, CURLOPT_POST, TRUE);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $post_str);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
    $obj = curl_exec($ch);
    curl_close($ch);

    // Decode json response
    $result = json_decode($obj);

    // Get playlists from the items object
    $playlists = $result->{'items'};

    //var_dump($playlists); 

    // For each playlist...
    foreach ($playlists as $playlist){
        foreach ($playlist->{'videos'} as $video){
            // Convert the creation date to something not so robotic..
            $creation_date_ms = $video->creationDate;
            $creation_date_s = $creation_date_ms / 1000;
            $date = date('Ymd',$creation_date_s);
            $time = strtotime($date);
            //echo $time."<br />";

            // and set the reference id for each video.
            $ref_id = $video->referenceId;

            // Phew! Now, let's first check that there is a reference id for the video. If not, no biggie.
            switch ($ref_id) {
                case "":
                    break;
                default:
                    // If so, run the function to create an xml object for that video!
                    if ($time <= strtotime('20100519')) {
                        $xml_code[$i] .= reencode_from_existing_source($ref_id);
                    }
                    break;
            }        
        }
    }
    // Finish him.
    $xml_code[$i] .= '</publisher-upload-manifest>';
    return($xml_code[$i]);
} //endxml


// Creates an xml object for the passed reference id.
function reencode_from_existing_source($ref_id){
   $xml_obj = '<reencode-from-existing-source
   title-refid="' . $ref_id . '"
   encode-to="MP4"
   encode-multiple="TRUE"
   overwrite-images="FALSE" />' . "\n";
   return ($xml_obj);
}

感谢任何能提供帮助的人!

Answer 1

我会使用 SimpleXML或内置于 PHP 中的 DOM 功能来生成 XML - 它非常强大，您只需传入属性名称、值和节点。

关于为什么您每次都得到相同的结果，您每次都发出相同的 CURL 请求，所以您希望得到相同的结果。