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java - 如何将 XML 读取到 Java 中的 POJO 列表?

转载 作者:数据小太阳 更新时间:2023-10-29 02:38:47 26 4
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我是 XML 的新手,我正在尝试读取 XML 页面并将其内容存储在数组列表中。

到目前为止,我似乎已经能够让 arraylist 填充第一个内容,因为当我尝试 isEmpty 时,它返回 false。所以肯定有东西。但是,当我尝试调用覆盖的 tostring 方法,或者甚至尝试为此调用任何单独的类别时,它只是返回空?

谁能帮忙?

这是我正在使用的代码:

package test;

import java.io.File;
import java.util.ArrayList;

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;

public class xmlmx {

public static void main(String[] args) {
ArrayList<Anime> list = new ArrayList<Anime>();
try {
File inputFile = new File("c:\\code\\ad\\XMLDB.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
System.out.println("Root element: " + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("Anime");
System.out.println("----------------------------");

for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
System.out.println("\nCurrent Element :" + nNode.getNodeName());

if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
list.add(new Anime(eElement.getAttribute("ID"),
eElement.getAttribute("name"),
eElement.getAttribute("altname"),
eElement.getAttribute("seasons"),
eElement.getAttribute("episodes"),
eElement.getAttribute("status"),
eElement.getAttribute("DS"),
eElement.getAttribute("have"),
eElement.getAttribute("left"),
eElement.getAttribute("plot"),
eElement.getAttribute("connect"),
eElement.getAttribute("image")));
System.out.println(list.get(0).toString());
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}

arraylist是anime类型的,这里有一个类:

    package test;

class Anime{
private String ID;
private String name;
private String altname;
private String seasons;
private String episodes;
private String status;
private String DS;
private String have;
private String left;
private String plot;
private String connect;
private String image;

public Anime(String ID,
String name,
String altname,
String seasons,
String episodes,
String status,
String DS,
String have,
String left,
String plot,
String connect,
String image) {
this.ID = ID;
this.name = name;
this.altname = altname;
this.seasons = seasons;
this.episodes = episodes;
this.status = status;
this.DS = DS;
this.have = have;
this.left = left;
this.plot = plot;
this.connect = connect;
this.image = image;
}

/*
getters and setters here...
*/
@Override
public String toString() {
return "Anime [ID=" + ID +
", name=" + name +
", altname=" + altname +
", seasons=" + seasons +
", episodes=" + episodes +
", status=" + status +
", DS=" + DS +
", have=" + have +
", left=" + left +
", plot=" + plot +
", connect=" + connect +
", image=" + image + "]";
}
}

最后,这是 xml:

<?xml version="1.0" encoding="UTF-8"?>
<Anime>
<record ID="BL1">
<name>Bleach</name>
<altname>Burichi</altname>
<seasons>16</seasons>
<episodes>366</episodes>
<status>Finished</status>
<sound>Dubbed</sound>
<have>All</have>
<left>-/-</left>
<plot>Ichigo gets grim reaper powers, fights reapers, hollows and everything in between</plot>
<connect>Bleach movies</connect>
<image>images/bleach.jpg</image>
</record>
</Anime>

非常感谢任何帮助,谢谢

最佳答案

您好,基本上您对 w3c dom xml 元素的理解是错误的。 “name:,”altname”等不是“Animie”元素的属性。那些是“record”节点的“子节点”。所以首先你必须通过迭代“Animie”元素的子节点来获取“record”节点。然后您可以遍历“record”元素的子节点,以便填充您的 Anime 对象。

这是您的“有效的 xmlmx 类”的简单实现。我不得不使用映射,因为您省略了 setter 方法,这可以通过尝试修复您头脑中的 xml 概念来改进。

用这个替换你的类。

package test;

import java.io.File;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Map;

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;

import com.sun.org.apache.xerces.internal.dom.DeferredElementImpl;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;

public class xmlmx {

public static void main(String[] args) {
ArrayList<Anime> list = new ArrayList<Anime>();
try {
File inputFile = new File("test.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
System.out.println("Root element: " + doc.getDocumentElement().getNodeName());

Node recordNode = null;
NodeList childNodes = doc.getFirstChild().getChildNodes();
for (int i = 0; i < childNodes.getLength(); i++) {
if (childNodes.item(i).getNodeName().equals("record")) {
recordNode = childNodes.item(i);
break;
}
}
System.out.println("----------------------------");


Map<String, String> map = new HashMap<>();
if (recordNode != null) {
NodeList subNodes = recordNode.getChildNodes();
for (int i = 0; i < subNodes.getLength(); i++) {
if (subNodes.item(i).getNodeType() == Node.ELEMENT_NODE) {
map.put(subNodes.item(i).getNodeName(), subNodes.item(i).getTextContent());
}
}
}

String id = ((DeferredElementImpl) recordNode).getAttribute("ID");
list.add(new Anime(id,
map.get("name"),
map.get("altname"),
map.get("seasons"),
map.get("episodes"),
map.get("status"),
map.get("DS"),
map.get("have"),
map.get("left"),
map.get("plot"),
map.get("connect"),
map.get("image")));

System.out.println(list.get(0));


} catch (Exception e) {
e.printStackTrace();
}
}
}

关于java - 如何将 XML 读取到 Java 中的 POJO 列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47711679/

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