xml - 我想将一个 xml 文件序列化为 java 对象

Question

我有这个 xml 文件，我想将它解压缩到一个 java 对象中。我正在使用 MOXy JAXB 库。

test.xml

    <?xml version="1.0" encoding="UTF-8"?>

<project >
    <type>org.netbeans.modules.ant.freeform</type>
            <compilation-unit>
                <package-root>src</package-root>
                <classpath mode="boot">${sunspot.bootclasspath}</classpath>
                <classpath mode="compile">${sunspot.classpath}</classpath>
                <built-to>build</built-to>
                <source-level>1.4</source-level>
            </compilation-unit>

</project>

这是我的java类:Project.java

package example;

import java.util.List;

import javax.xml.bind.annotation.*;


import org.eclipse.persistence.oxm.annotations.XmlPath;

@XmlRootElement
@XmlType(name = "project",propOrder = {"type", "compilation_unit"})
public class Project {
    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    private String type;


    @XmlPath("/compilation-unit")
    @XmlElement(name = "compilation-unit")
    private CompilationUnit compilation_unit;

    public CompilationUnit getPckg() {
        return compilation_unit;
    }

    public void setPckg(String pckg) {
        this.compilation_unit = compilation_unit;
    }


}

编译单元

package example;

import org.eclipse.persistence.oxm.annotations.XmlPath;

import javax.xml.bind.annotation.XmlType;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import java.util.List;

/**
 * Created by IntelliJ IDEA.
 * User: ronny
 * Date: Aug 5, 2010
 * Time: 11:28:37 AM
 * To change this template use File | Settings | File Templates.
 */
@XmlType(name = "compilation-unit", propOrder = {"package_root","built_to" ,"source_level" ,"classpath"})

public class CompilationUnit {
    public String getPackage_root() {
        return package_root;
    }

    public void setPackage_root(String package_root) {
        this.package_root = package_root;
    }

    public String getBuilt_to() {
        return built_to;
    }

    public void setBuilt_to(String built_to) {
        this.built_to = built_to;
    }

    public String getSource_level() {
        return source_level;
    }

    public void setSource_level(String source_level) {
        this.source_level = source_level;
    }

    public List<Classpath> getClasspath() {
        return classpath;
    }

    public void setClasspath(List<Classpath> classpath) {
        this.classpath = classpath;
    }

    private String package_root;
    private String built_to;
    private String source_level;
    private List<Classpath> classpath;

}

类路径:

package example;

import javax.xml.bind.annotation.XmlAttribute;

/**
 * Created by IntelliJ IDEA.
 * User: leontiad
 * Date: Aug 5, 2010
 * Time: 11:33:52 AM
 * To change this template use File | Settings | File Templates.
 */
public class Classpath {
    @XmlAttribute
    private String mode;
}

和用于测试的Demo类:

package example;

import java.io.FileInputStream;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Project.class);

        FileInputStream xml = new FileInputStream("C:\\task.xml");
        Project project = (Project) jc.createUnmarshaller().unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(project, System.out);
    }
}

我得到的输出如下:

<?xml version="1.0" encoding="UTF-8"?>
<project>
   <type>org.netbeans.modules.ant.freeform</type>
</project>

谁能帮助理解为什么不打印整个 xml 文件而只打印其中的一部分？

Answer 1

我没有经常使用 JAXB，但我认为 compilation_unit 字段不需要 @XmlPath("/compilation-unit")。我觉得反序列化xml的时候路径注解和xml不匹配。