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xml - 无法使用 XML 架构和 Perl (XML::LibXML) 验证 XML

转载 作者:数据小太阳 更新时间:2023-10-29 02:36:45 27 4
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xml:

<?xml version="1.0"?>
<workers xmlns="http://www.zoo.com"
xmlns:xs="http://www.w3.org/2001/XMLSchema-instance"
xs:schemaLocation="http://www.zoo.com worker.xsd">
<impiegato>
<username>mario</username>
<password>de2f15d014d40b93578d255e6221fd60</password>
<nome>Mario</nome>
<sesso>F</sesso>
<eta>23</eta>
</impiegato>
<impiegato>
<username>maria</username>
<password>maria</password>
<nome>Mariaaa</nome>
<sesso>F</sesso>
<eta>443</eta>
</impiegato>
<impiegato>
<username>mirco</username>
<password>mirco</password>
<nome>Mirco</nome>
<sesso>F</sesso>
<eta>27</eta>
</impiegato>
<impiegato>
<username>martina</username>
<password>martina</password>
<nome>Martina</nome>
<sesso>M</sesso>
<eta>26</eta>
</impiegato>
<manager>
<username>marco</username>
<password>marco</password>
<nome>Marco</nome>
<sesso>M</sesso>
<eta>25</eta>
</manager>
<manager>
<username>giovanna</username>
<password>zxVcGz0BPdHkY</password>
<nome>Giovanna</nome>
<sesso>F</sesso>
<eta>24</eta>
</manager>
<manager>
<username>lucanervi</username>
<password>zxePlNSDQjsxg</password>
<nome>Luca Nervi</nome>
<sesso>M</sesso>
<eta>23</eta>
</manager>
</workers>

XML 模式:

<?xml version="1.0"?>
<xs:schema
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:zoo="http://www.zoo.com"
targetNamespace="http://www.zoo.com"
elementFormDefault="qualified">

<xs:element name="workers" type="zoo:Tworkers"/>

<xs:complexType name="Tworkers">
<xs:sequence maxOccurs="unbounded">
<xs:element name="impiegato" type ="zoo:Timpiegato" minOccurs="0" />
<xs:element name="manager" type ="zoo:Tmanager" minOccurs="0"/>
</xs:sequence>
</xs:complexType>

<xs:complexType name="Timpiegato">
<xs:sequence>
<xs:element name="username" type ="xs:string"/>
<xs:element name="password" type ="xs:string"/>
<xs:element name="nome" type ="xs:string"/>
<xs:element name="sesso" type ="xs:string"/>
<xs:element name="eta" type ="xs:integer"/>
</xs:sequence>
</xs:complexType>

<xs:complexType name="Tmanager">
<xs:sequence>
<xs:element name="username" type ="xs:string"/>
<xs:element name="password" type ="xs:string"/>
<xs:element name="nome" type ="xs:string"/>
<xs:element name="sesso" type ="xs:string"/>
<xs:element name="eta" type ="xs:integer"/>
</xs:sequence>
</xs:complexType>

</xs:schema>

当我使用 XML::LibXML::Schema 验证 xml 时,我得到:

../xml/workers.xml:0: Schemas validity error : Element 'impiegato': This element is not expected. Expected is one of ( {http://www.zoo.com}impiegato, {http://www.zoo.com}manager ).

Perl 代码:

my $parser = XML::LibXML->new;
my $doc = $parser->parse_file("../xml/workers.xml");
my $xmlschema = XML::LibXML::Schema->new( location => "../xml/worker.xsd" );
$xmlschema->validate($doc);

我认为这是命名空间的问题,但不知道该怎么办。

附录:

我试图从 XML 架构中删除 elementFormDefault="qualified"属性。现在我有相反的错误:

../xml/workers.xml:0: Schemas validity error : Element '{http://www.zoo.com}impiegato':
This element is not expected. Expected is one of ( impiegato, manager ).

最佳答案

用 Saxon 验证这一点,它对我有用。我认为您运行验证的方式一定有误。

关于xml - 无法使用 XML 架构和 Perl (XML::LibXML) 验证 XML,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11064258/

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