java - 从java中的xml中提取文本

Question

我正在尝试为 android 创建一个 rss 阅读器。所以我连接到 rss ulr 并获取一些 XML 信息。这是链接 - http://www.bulgarianhistory.org/feed/如果打开它查看源代码，您会注意到有一个标签content:encoded。我怎样才能得到这个标签内的信息？我的代码只是跳过它!我正在使用 SAX。这是我的解析器类:

public class RSSParser extends DefaultHandler {
    private final static String TAG_ITEM = "item";
    private final static String[] xmltags = { "title", "link", "pubDate", "description", "content" };

    private RSSItem currentitem = null;
    private ArrayList<RSSItem> itemarray = null;
    private int currentindex = -1;
    private boolean isParsing = false;
    private StringBuilder builder = new StringBuilder();

    public RSSParser(ArrayList<RSSItem> itemarray) {
        super();

        this.itemarray = itemarray;
    }

    @Override
        public void characters(char[] ch, int start, int length) throws SAXException {
            super.characters(ch, start, length);

            if(isParsing && -1 != currentindex && null != builder)
            {
                builder.append(ch,start,length);
            }
        }

    @Override
        public void startElement(String uri, String localName, String qName,Attributes attributes) throws SAXException {
            super.startElement(uri, localName, qName, attributes);

            if(localName.equalsIgnoreCase(TAG_ITEM))
            {
                currentitem = new RSSItem();
                currentindex = -1;
                isParsing = true;

                itemarray.add(currentitem);
            }
            else
            {
                currentindex = itemIndexFromString(localName);

                builder = null;

                if(-1 != currentindex)
                    builder = new StringBuilder();
            }
        }

    @Override
        public void endElement(String uri, String localName, String qName) throws SAXException {
            super.endElement(uri, localName, qName);

            if(localName.equalsIgnoreCase(TAG_ITEM))
            {
                isParsing = false;
            }
            else if(currentindex != -1)
            {
                if(isParsing)
                {
                    switch(currentindex)
                    {
                        case 0: currentitem.title = builder.toString();                 break;
                        case 1: currentitem.link = builder.toString();                  break;
                        case 2: currentitem.date = builder.toString();                  break;
                        case 3: currentitem.description= builder.toString();            break;
                        case 4: currentitem.content = builder.toString();               break;
                    }
                }
            }
        }

    private int itemIndexFromString(String tagname){
        int itemindex = -1;

        for(int index= 0; index<xmltags.length; ++index)
        {
            if(tagname.equalsIgnoreCase(xmltags[index]))
            {
                itemindex = index;

                break;
            }
        }

        return itemindex;
    }
}

Answer 1

我真的建议不要使用 Sax在 Android 上，因为据我所知，它在 Android 上的性能真的很慢。你应该使用 XmlPullParser 附带 Android ，因此无需添加任何外部 jars而且您还将获得显着的性能改进。我刚刚测试过 XmlPullParser将解析 <content:encoded>标记与任何其他标记一样，因此它会起作用。