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java - jackson 反序列化具有相同名称的xml字段

转载 作者:数据小太阳 更新时间:2023-10-29 02:33:04 26 4
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我想将来自 HTTP 请求的 XML 响应反序列化为 POJO 列表。我遇到的问题是 XML 对包含不同值的元素使用相同的名称“属性”。

<nowplaying-info-list>
<nowplaying-info mountName="FGDGFD" timestamp="1559761606" type="track">
<property name="cue_time_duration">
<![CDATA[262000]]>
</property>
<property name="cue_time_start">
<![CDATA[1559761571830]]>
</property>
<property name="cue_title">
<![CDATA[Marine marchande]]>
</property>
<property name="track_album_name">
<![CDATA[Octobre]]>
</property>
<property name="track_artist_name">
<![CDATA[Les Cowboys Fringants]]>
</property>
<property name="track_id">
<![CDATA[8133]]>
</property>
</property>
</nowplaying-info>
...
@JacksonXmlRootElement(localName = "nowplaying-info")
public class ScheduleItem implements Serializable {
@JacksonXmlProperty(localName = "property")
private String song = null;
private String artist = null;
private String cover = null;
private Long datetime = null;

我想将名称为 cue_title 的属性序列化为歌曲变量,将名称为 cue_time_start 的属性序列化为日期时间。

最佳答案

字段和列表之间没有简单的映射。我建议创建单独的模型,将 XML 有效负载反序列化到它,然后转换为所需的 POJO。下面的例子展示了这个想法:

import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlText;
import java.io.File;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
import org.apache.commons.lang3.StringUtils;

public class XmlApp {

public static void main(String[] args) throws Exception {
System.out.println(new File(".").getAbsolutePath());
File xml = new File("./src/main/resources/test.xml");
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.setDefaultUseWrapper(false);
xmlMapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);

TypeReference<List<NowPlayingInfo>> type = new TypeReference<List<NowPlayingInfo>>() {
};
List<NowPlayingInfo> infos = xmlMapper.readValue(xml, type);
List<ScheduleItem> items = infos.stream()
.map(NowPlayingInfo::getPropertiesAsMap)
.map(m -> {
ScheduleItem item = new ScheduleItem();
item.setSong(m.get("cue_title"));
item.setDatetime(Long.parseLong(m.get("cue_time_start")));
return item;
}).collect(Collectors.toList());
items.forEach(System.out::println);
}
}

class ScheduleItem {

private String song;
private String artist;
private String cover;
private Long datetime;

//getters, setters, toString
}

class NowPlayingInfo {

private String mountName;
private long timestamp;
private String type;

@JsonProperty("property")
private List<Property> properties;

public Map<String, String> getPropertiesAsMap() {
Map<String, String> map = new LinkedHashMap<>();
properties.forEach(p -> map.put(p.getName(), StringUtils.strip(p.getValue())));
return map;
}

//getters, setters, toString
}

class Property {

@JacksonXmlText
private String value;

@JacksonXmlProperty(isAttribute = true)
private String name;

//getters, setters, toString
}

上面的 XML 打印应用:

ScheduleItem{song='Marine marchande', artist='null', cover='null', datetime=1559761571830}

关于java - jackson 反序列化具有相同名称的xml字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56467014/

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