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java - Unmarshalexception 意外元素,预期元素是(无)

转载 作者:数据小太阳 更新时间:2023-10-29 02:29:44 26 4
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当我想反序列化已从字节数组序列化的 JAXBElement 时遇到问题。我有异常(exception):

Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"Avizo"). Expected elements are (none)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.handleEvent(UnmarshallingContext.java:647)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:243)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:238)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportUnexpectedChildElement(Loader.java:105)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext$DefaultRootLoader.childElement(UnmarshallingContext.java:1048)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext._startElement(UnmarshallingContext.java:483)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.startElement(UnmarshallingContext.java:465)

这是我的代码:

public class JAXBTest {

public static byte[] serialize(JAXBElement<AvizoType> xmlData) throws Exception {
// Result stream buffer
ByteArrayOutputStream bos = new ByteArrayOutputStream();

final JAXBContext jaxbContext = JAXBContext.newInstance(AvizoType.class);

final Marshaller marshaller = jaxbContext.createMarshaller();
marshaller.marshal(xmlData, new StreamResult(bos));

return bos.toByteArray();
}

public static JAXBElement<AvizoType> deserialize(byte[] data) throws Exception {
// Result stream buffer
ByteArrayInputStream bis = new ByteArrayInputStream(data);

final JAXBContext jaxbContext = JAXBContext.newInstance(AvizoType.class);

final Unmarshaller marshaller = jaxbContext.createUnmarshaller();

return (JAXBElement<AvizoType>) marshaller.unmarshal(bis);
}

public static void main(String[] args) throws Exception {
AvizoType type = new AvizoType();
type.setAvizoId(1);

JAXBElement<AvizoType> element = new JAXBElement(new QName("Avizo"), AvizoType.class, type);

byte[] result = serialize(element);
deserialize(result);

}
}

avizoType 是从 xsd 生成的类:

    //
// This file was generated by the JavaTM Architecture for XML Binding(JAXB) Reference Implementation, v2.2.10-b140310.1920
// See <a href="http://java.sun.com/xml/jaxb">http://java.sun.com/xml/jaxb</a>
// Any modifications to this file will be lost upon recompilation of the source schema.
// Generated on: 2015.03.23 at 01:59:39 PM CET
//


import java.io.Serializable;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlType;

/**
* <p>
* Java class for AvizoType complex type.
*
* <p>
* The following schema fragment specifies the expected content contained within this class.
*
* <pre>
* &lt;complexType name="AvizoType">
* &lt;complexContent>
* &lt;restriction base="{http://www.w3.org/2001/XMLSchema}anyType">
* &lt;sequence>
* &lt;element name="AvizoId" type="{http://www.w3.org/2001/XMLSchema}long"/>
* &lt;/sequence>
* &lt;/restriction>
* &lt;/complexContent>
* &lt;/complexType>
* </pre>
*
*
*/

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "AvizoType", propOrder = { "avizoId" })
public class AvizoType implements Serializable {

@XmlElement(name = "AvizoId")
protected long avizoId;

/**
* Gets the value of the avizoId property.
*
*/
public long getAvizoId() {
return avizoId;
}

/**
* Sets the value of the avizoId property.
*
*/
public void setAvizoId(long value) {
this.avizoId = value;
}

}

最佳答案

您的类 AvizoType 旁边应该有一个名为 ObjectFactory 的类。如果是这样,请尝试这种方法:

final JAXBContext jaxbContext = JAXBContext.newInstance(ObjectFactory.class);
return ((JAXBElement<AvizoType>) jaxbContext.createUnmarshaller().unmarshal(
inputStream)).getValue();

关于java - Unmarshalexception 意外元素,预期元素是(无),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29229308/

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