java - 多类型List注解翻译: JAXB to SimpleXML

Question

我正在尝试将一些 JAXB xjc.exe 生成的类转换为简单 XML 类。我不确定如何注释动态元素。例如，在架构中，我有:

<!-- Message Set Request/Response Pairs and contained requests  -->
<xsd:element name="QBXMLMsgsRq">
    <xsd:complexType>
        <xsd:choice minOccurs="0" maxOccurs="unbounded">
            <xsd:element name="HostQueryRq" type="HostQueryRqType"/>
            <xsd:element name="CompanyQueryRq" type="CompanyQueryRqType"/>
            <xsd:element name="CompanyActivityQueryRq" type="CompanyActivityQueryRqType"/>
            <!-- many more of these choices -->
        </xsd:choice>
        <xsd:attribute name="oldMessageSetID" type="STRTYPE"/>
        <!-- some other attributes -->
    </xsd:complexType>
</xsd:element>

当通过 xjc.exe 运行时，为 @XmlElement 生成以下注释

@XmlElements({
    @XmlElement(name = "HostQueryRq", type = HostQueryRqType.class),
    @XmlElement(name = "CompanyQueryRq", type = CompanyQueryRqType.class),
    @XmlElement(name = "CompanyActivityQueryRq", type = CompanyActivityQueryRqType.class),
    //+ et al
})
protected List<Object> hostQueryRqOrCompanyQueryRqOrCompanyActivityQueryRq;

那么我怎样才能将这个 JAXB 结构转换为一个 SimpleXML 注释类结构呢？

Answer 1

答案是使用ElementListUnion以确定列表类型的可用选项。检查here在“在一个列表中收集各种类型”下。示例:

@Root
public class Example {

   @ElementListUnion({
      @ElementList(entry="int", type=Integer.class, inline=true),
      @ElementList(entry="date", type=Date.class, inline=true),
      @ElementList(entry="text", type=String.class, inline=true)
   })
   private List<Object> list;
}