c# - 使用 XML 序列化将属性放入不同的 XML 命名空间

Question

我正在使用 VSTS2008 + C# + .Net 3.0。我正在使用下面的代码来序列化 XML，这是我当前的代码和序列化的 XML 文件。我的目的是让 MyInnerObjectProperties 属于一个特殊的 XML 命名空间 ( http://foo/2009 ) 并将此命名空间设为默认命名空间。有什么想法可以实现吗？

当前输出:

<?xml version="1.0"?>
<MyClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <MyObjectProperty>
    <MyInnerObjectProperties>
      <MyInnerObjectProperty>
        <ObjectName>Foo Type</ObjectName>
      </MyInnerObjectProperty>
      <MyInnerObjectProperty>
        <ObjectName>Goo Type</ObjectName>
      </MyInnerObjectProperty>
    </MyInnerObjectProperties>
  </MyObjectProperty>
</MyClass>

当前代码:

public class MyClass
{
    private MyObject[] _myObjectProperty;

    [XmlElement(IsNullable=false)]
    public MyObject[] MyObjectProperty
    {
        get
        {
            return _myObjectProperty;
        }
        set
        {
            _myObjectProperty = value;
        }
    }
}
public class MyObject
{
    private MyInnerObject[] _myInnerObjectProperty;

    [XmlArrayItemAttribute("MyInnerObjectProperty", typeof(MyInnerObject),  IsNullable=false)]
    public MyInnerObject[] MyInnerObjectProperties
    {
        get
        {
            return _myInnerObjectProperty;
        }
        set
        {
            _myInnerObjectProperty = value;
        }
    }
}

public class MyInnerObject
{
    public string ObjectName;
}

public class Program
{
    static void Main(string[] args)
    {
        XmlSerializer s = new XmlSerializer(typeof(MyClass));
        FileStream fs = new FileStream("foo.xml", FileMode.Create);
        MyClass instance = new MyClass();
        instance.MyObjectProperty = new MyObject[1];
        instance.MyObjectProperty[0] = new MyObject();
        instance.MyObjectProperty[0].MyInnerObjectProperties = new MyInnerObject[2];
        instance.MyObjectProperty[0].MyInnerObjectProperties[0] = new MyInnerObject();
        instance.MyObjectProperty[0].MyInnerObjectProperties[0].ObjectName = "Foo Type";
        instance.MyObjectProperty[0].MyInnerObjectProperties[1] = new MyInnerObject();
        instance.MyObjectProperty[0].MyInnerObjectProperties[1].ObjectName = "Goo Type";

        s.Serialize(fs, instance);

        return;
    }
}

Answer 1

这个怎么样:

[XmlArrayItemAttribute( Namespace = "http://foo.com/2009" /* other attr. params. */ )]
public MyInnerObject[] MyInnerObjectProperties
{
    get { ... }
    set { ... }
}