作者热门文章
- xml - AJAX/Jquery XML 解析
- 具有多重继承的 XML 模式
- .net - 枚举序列化 Json 与 XML
- XML 简单类型、简单内容、复杂类型、复杂内容
这是我的 SQL。我似乎无法从这件事中得到一个单一的值(value)。仅当我删除所有 xmlns 属性时它才有效。
我认为问题在于此 xml 包含 2 个默认 namespace ,一个附加到 Response 元素,一个附加到 Shipment 元素。
DECLARE @xml XML
SET @xml = '<TrackResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Response xmlns="http://www.ups.com/XMLSchema/XOLTWS/Common/v1.0">
<ResponseStatus>
<Code>1</Code>
<Description>Success</Description>
</ResponseStatus>
<TransactionReference />
</Response>
<Shipment xmlns="http://www.ups.com/XMLSchema/XOLTWS/Track/v2.0">
<InquiryNumber>
<Code>01</Code>
<Description>ShipmentIdentificationNumber</Description>
<Value>1ZA50209234098230</Value>
</InquiryNumber>
<ShipperNumber>A332098</ShipperNumber>
<ShipmentAddress>
<Type>
<Code>01</Code>
<Description>Shipper Address</Description>
</Type>
<Address>
<AddressLine>123 HWY X</AddressLine>
<City>SOMETOWN</City>
<StateProvinceCode>SW</StateProvinceCode>
<PostalCode>20291 1234</PostalCode>
<CountryCode>US</CountryCode>
</Address>
</ShipmentAddress>
<ShipmentWeight>
<UnitOfMeasurement>
<Code>LBS</Code>
</UnitOfMeasurement>
<Weight>0.00</Weight>
</ShipmentWeight>
<Service>
<Code>42</Code>
<Description>UPS GROUND</Description>
</Service>
<Package>
<TrackingNumber>1ZA50209234098230</TrackingNumber>
<PackageServiceOption>
<Type>
<Code>01</Code>
<Description>Signature Required</Description>
</Type>
</PackageServiceOption>
<Activity>
<ActivityLocation>
<Address>
<City>SOMEWHERE</City>
<StateProvinceCode>PA</StateProvinceCode>
<CountryCode>US</CountryCode>
</Address>
</ActivityLocation>
<Status>
<Type>X</Type>
<Description>Damage reported. / Damage claim under investigation.</Description>
<Code>UY</Code>
</Status>
<Date>20120424</Date>
<Time>125000</Time>
</Activity>
<Activity>
<ActivityLocation>
<Address>
<City>SOMEWHERE</City>
<StateProvinceCode>PA</StateProvinceCode>
<CountryCode>US</CountryCode>
</Address>
</ActivityLocation>
<Status>
<Type>X</Type>
<Description>All merchandise discarded. UPS will notify the sender with details of the damage.</Description>
<Code>GY</Code>
</Status>
<Date>20120423</Date>
<Time>115500</Time>
</Activity>
<PackageWeight>
<UnitOfMeasurement>
<Code>LBS</Code>
</UnitOfMeasurement>
<Weight>0.00</Weight>
</PackageWeight>
</Package>
</Shipment>
</TrackResponse>'
select Svc.Dsc.value('(/TrackResponse/Shipment/Service/Description)[1]', 'varchar(25)')
from @xml.nodes('/TrackResponse') as Svc(Dsc)
最佳答案
正如@marc_s 所说,您忽略了 xml 命名空间。 Here is a sql fiddle example .这给 X,我认为这就是您所需要的。 Read this article for more .注意:*:TrackResponse[1]/*:
在 xpath
--Results: X
declare @xmlTable as table (
xmlData xml
)
insert into @xmlTable
select '<TrackResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Response xmlns="http://www.ups.com/XMLSchema/XOLTWS/Common/v1.0">
...
</TrackResponse>'
;with xmlnamespaces(default 'http://www.ups.com/XMLSchema/XOLTWS/Track/v2.0')
select
x.xmlData.value('(/*:TrackResponse[1]/*:Shipment[1]/Package[1]/Activity[1]/Status[1]/Type[1])','varchar(100)') as all_snacks
from @xmlTable x
关于sql - 在 SQL Server 中给定以下 XML,如何获取值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13980321/
我是一名优秀的程序员,十分优秀!