Python 独有的 XML 规范化 (xml-exc-c14n)

Question

在 Python 中，我需要规范化 (c14n) XML 字符串。

我可以为此使用哪个模块/包？我应该怎么做？

(我更喜欢使用默认的 python 2.7 模块，无需额外安装或补丁。)

引用:http://www.w3.org/TR/xml-exc-c14n/

Answer 1

来自 http://www.decalage.info/en/python/lxml-c14n

lxml provides a very easy way to do c14n in python. <..>

Here is an example showing how to perform C14N using lxml 2.1:

import lxml.etree as ET
et = ET.parse('file.xml')
output = StringIO.StringIO()
et.write_c14n(output)
print output.getvalue()

来自 lxml 文档:

write_c14n(self, file, exclusive=False, with_comments=True, compression=0, inclusive_ns_prefixes=None)

C14N write of document. Always writes UTF-8.

<..>

还有libxml2:

XML C14N version 1.0 provides two options which make four possibilities (see http://www.w3.org/TR/xml-c14n and http://www.w3.org/TR/xml-exc-c14n/):

• Inclusive or Exclusive C14N
• With or without comments

libxml2 gives access to these options in its C14N API: http://xmlsoft.org/html/libxml-c14n.html

虽然必须检查这两个库中的版本更改。