C#类序列化映射

Question

我正在寻找有关如何实现和/或更改一般以下类的类序列化行为的提示和想法。

简化的(不完整的)示例类:

[Serializable]
public class Choobakka
{
    public string Name { get; set; }
    public VariableList<Item> Stuff { get; set; }
}
[Serializable]
public class Item
{
    public string Name { get; set; }
    public string Value { get; set; }
}
[Serializable]
public sealed class VariableList<T> : AVariableList<T>
{
    public new ItemList<T> Items { get { return _items; } set { _items = value; } }
    public new bool IsNull { get { return Items == null; } }
    public new bool IsEmpty { get { return IsNull || Count <= 0; } }
    public new int Count { get { return IsNull ? 0 : this.Items.Count; } }
    public new string CountAsString { get { return Count.ToString(); } }
    public VariableList()
    {
        _items = new ItemList<T>();
    }
}

这就是我填写和连载 Choobakka 的东西的方式

var choobakka = new Choobakka() { Name = "CHOO-BAKKA", Stuff = new VariableList<Item>()  };            
choobakka.Stuff.Items.Add( new Item() { Name = "passport", Value = "lv" } );
choobakka.Stuff.Items.Add( new Item() { Name = "wallet", Value = "50euro" } );
StringBuilder sb = new StringBuilder();
using (TextWriter tw = new StringWriter(sb))
{
    XmlSerializer xs = new XmlSerializer(typeof(Choobakka));
    xs.Serialize(tw, choobakka);
}

序列化的 XML 看起来像:

<Choobakka>
    <Name>CHOO-BAKKA</Name>
    <Stuff>
        <Items>
            <Item>
                <Name>passport</Name>
                <Value>lv</Value>
            </Item>
            <Item>
                <Name>wallet</Name>
                <Value>50euro</Value>
            </Item>
        </Items>
    </Stuff>
</Choobakka>

现在的问题是您建议如何获得 <Items> 的装备标记(如果可能)类似

<Choobakka>
    <Name>CHOO-BAKKA</Name>
    <Stuff>
        <Item>
            <Name>passport</Name>
            <Value>lv</Value>
        </Item>
        <Item>
            <Name>wallet</Name>
            <Value>50euro</Value>
        </Item>
    </Stuff>
</Choobakka>

话虽如此，我无法更改 VariableList<T> 的结构类，除了应用一些 XML 序列化属性。

这样做的原因不仅是简化生成的 XML，而且还对 SQL Server 查询生成的 XML 进行反序列化。我有属性的想法，xsd/xslt转换...

Answer 1

如果你不能改变VariableList<> , 然后改变 Choobaka会做

public class Choobakka
{
    public string Name { get; set; }
    [XmlIgnore]
    public VariableList<Item> Stuff { get; set; } // we do not serialize this
    [XmlArray("Stuff")]
    public Item[] _Stuff // but this
    {
        get
        {
            // get Item[] from Stuff property somehow
            // ...

            // as test
            return new Item[] {new Item() { Name = "1", Value = "111"}, new Item() { Name = "2", Value = "222"}};
        }
        set
        {
            // set Stuff property from Item[] somehow
            // ...
        }
    }
}

产生(proof)

<?xml version="1.0" encoding="utf-16"?>
<Choobakka xmlns:xsd="http://www.w3.org/2001/XMLSchema"             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Name>CHOO-BAKKA</Name>
  <Stuff>
    <Item>
      <Name>1</Name>
      <Value>111</Value>
    </Item>
    <Item>
      <Name>2</Name>
      <Value>222</Value>
    </Item>
  </Stuff>
</Choobakka>