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java - Jackson XML 反序列化问题

转载 作者:数据小太阳 更新时间:2023-10-29 02:11:50 26 4
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我能够编写 XML 文档,但是无法反序列化创建的 XML。原始代码在 Kotlin 中,但我发布了 Java 等效代码。

@JacksonXmlRootElement(localName = "assets")
public class Assets {
@JacksonXmlElementWrapper(useWrapping = false)
private Asset[] asset;

public Assets(Asset[] asset) {
this.asset = asset;
}

public Asset[] getAsset() {
return asset;
}

public void setAsset(Asset[] asset) {
this.asset = asset;
}
}

public class Asset {
@JacksonXmlProperty(isAttribute = true)
private String type;
@JacksonXmlProperty(isAttribute = true)
private String name;
@JacksonXmlProperty(isAttribute = true)
private String displayName;
@JacksonXmlElementWrapper(localName = "permissions")
private Permission[] permission;

public Asset(String type, String name, String displayName, Permission[] permission) {
this.type = type;
this.name = name;
this.displayName = displayName;
this.permission = permission;
}

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getDisplayName() {
return displayName;
}

public void setDisplayName(String displayName) {
this.displayName = displayName;
}

public Permission[] getPermission() {
return permission;
}

public void setPermission(Permission[] permission) {
this.permission = permission;
}
}

public class Permission {
@JacksonXmlProperty(isAttribute = true)
private String name;
private Group[] group;

public Permission(String name, Group[] group) {
this.name = name;
this.group = group;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public Group[] getGroup() {
return group;
}

public void setGroup(Group[] group) {
this.group = group;
}
}

用 (Kotlin) 实例化:

fun writeToXml(obj: Any) : String {
val xmlMapper = XmlMapper()
xmlMapper.enable(SerializationFeature.INDENT_OUTPUT)
return xmlMapper.writeValueAsString(obj)
}

val assets = Assets(arrayOf(
Asset("bdo", "approval-matrix", "Approval Matrix", arrayOf(Permission("Create", arrayOf(Group(arrayOf("Admin", "Approver")))))),
Asset("bdo", "approval-matrix-2", "Approval Matrix 2", arrayOf(Permission("Delete", arrayOf(Group(arrayOf("Admin", "Approver")), Group(arrayOf("Admin-2", "Approver-2"))))))))

val xmlModule = JacksonXmlModule()
val objectMapper = XmlMapper(xmlModule)
println(writeToXml(assets))

生成的 XML 符合预期:

<assets>
<asset type="bdo" name="approval-matrix" displayName="Approval Matrix">
<permissions>
<permission name="Create">
<groups>
<group>Admin</group>
<group>Approver</group>
</groups>
</permission>
</permissions>
</asset>
<asset type="bdo" name="approval-matrix-2" displayName="Approval Matrix 2">
<permissions>
<permission name="Delete">
<groups>
<group>Admin</group>
<group>Approver</group>
</groups>
<groups>
<group>Admin-2</group>
<group>Approver-2</group>
</groups>
</permission>
</permissions>
</asset>
</assets>

但是在尝试反序列化时:

val generated = objectMapper.readValue<Assets>(xmlAssets)

我收到以下错误:

Exception in thread "main" com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `uk.co.processflows.configuration.entities.Assets` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (StringReader); line: 2, column: 3]
at com.fasterxml.jackson.databind.exc.InvalidDefinitionException.from(InvalidDefinitionException.java:67)
at com.fasterxml.jackson.databind.DeserializationContext.reportBadDefinition(DeserializationContext.java:1451)
at com.fasterxml.jackson.databind.DeserializationContext.handleMissingInstantiator(DeserializationContext.java:1027)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.deserializeFromObjectUsingNonDefault(BeanDeserializerBase.java:1290)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:326)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:159)
at com.fasterxml.jackson.dataformat.xml.deser.WrapperHandlingDeserializer.deserialize(WrapperHandlingDeserializer.java:113)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4001)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3011)
at uk.co.processflows.module.EntryPoint.main(EntryPoint.kt:58)

如有任何帮助,我们将不胜感激。

最佳答案

只是为了澄清答案:

我包括

dependencies {
...
compile(kotlin("reflect"))
compile("com.fasterxml.jackson.module:jackson-module-kotlin:2.9.+")
compile("com.fasterxml.jackson.dataformat:jackson-dataformat-xml:2.9.+")
...
}

build.gradle.kts

然后遇到了同样的问题。通过向构造函数添加默认值来更改我的数据类似乎可以修复它。即:

数据类 HelloWorld(val hello: Boolean, val world: Boolean) <- 错误

成为

数据类 HelloWorld(val hello: Boolean = false, val world: Boolean = false) <- Working

然后:

const val xml = """
<HelloWorld>
<hello>true</hello>
<world>true</world>
</HelloWorld>
"""

将通过数据类在 kotlin 中正常序列化和反序列化。谢谢!

关于java - Jackson XML 反序列化问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50374541/

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