gpt4 book ai didi

xml - 用 R 解析 XML - 总是那么困难吗?

转载 作者:数据小太阳 更新时间:2023-10-29 02:08:40 26 4
gpt4 key购买 nike

我花了比预期更多的时间将 xml 传输到 dataframe(代码片段同时包含 xml 和 xmlTreeParse 以使 post 更小,整个解决方案在此之后):

users = xmlTreeParse(file=
'<?xml version="1.0" encoding="utf-8"?>
<users>
<row Id="-1" Reputation="1" CreationDate="2010-07-19T06:55:26.860" DisplayName="Community" LastAccessDate="2010-07-19T06:55:26.860" Location="on the server farm" AboutMe="some text" Views="0" UpVotes="4382" DownVotes="771" EmailHash="a007be5a61f6aa8f3e85ae2fc18dd66e" />
<row Id="2" Reputation="101" CreationDate="2010-07-19T14:01:36.697" DisplayName="Geoff Dalgas" LastAccessDate="2012-09-13T17:41:48.300" WebsiteUrl="http://stackoverflow.com" Location="Corvallis, OR" AboutMe="some text 2" Views="7" UpVotes="3" DownVotes="0" EmailHash="b437f461b3fd27387c5d8ab47a293d35" Age="36" />
<row Id="3" Reputation="101" CreationDate="2010-07-19T15:34:50.507" DisplayName="Jarrod Dixon" LastAccessDate="2013-01-15T03:28:47.657" WebsiteUrl="http://stackoverflow.com" Location="New York, NY" AboutMe="some text 3" Views="9" UpVotes="19" DownVotes="0" EmailHash="2dfa19bf5dc5826c1fe54c2c049a1ff1" Age="34" />
<row Id="4" Reputation="101" CreationDate="2010-07-19T19:03:27.400" DisplayName="Emmett" LastAccessDate="2013-04-16T16:51:04.780" WebsiteUrl="http://minesweeperonline.com" Location="New York, NY" AboutMe="some text 4" Views="3" UpVotes="0" DownVotes="0" EmailHash="129bc58fc3f1e3853cdd3cefc75fe1a0" Age="27" />
<row Id="5" Reputation="6182" CreationDate="2010-07-19T19:03:57.227" DisplayName="Shane" LastAccessDate="2013-02-05T11:23:09.587" WebsiteUrl="http://www.statalgo.com" Location="New York, NY" AboutMe="some text 5" Views="605" UpVotes="659" DownVotes="5" EmailHash="0cee97ffd90277bf4ac753331d50af60" Age="34" />
<row Id="6" Reputation="442" CreationDate="2010-07-19T19:04:07.647" DisplayName="Harlan" LastAccessDate="2013-05-09T13:11:29.027" WebsiteUrl="http://www.harlan.harris.name" Location="District of Columbia" AboutMe="some text 6" Views="30" UpVotes="42" DownVotes="0" EmailHash="9f1a68b9e623be5da422b44e733fa8bc" Age="40" />
<row Id="7" Reputation="329" CreationDate="2010-07-19T19:04:37.257" DisplayName="Vince" LastAccessDate="2013-05-21T22:49:10.237" WebsiteUrl="http://bioinformatics.ucdavis.edu" Location="Davis, CA" AboutMe="some text 7" Views="21" UpVotes="14" DownVotes="0" EmailHash="4f7cebc8ac200d15bac5dcff51469425" Age="27" />
<row Id="8" Reputation="6104" CreationDate="2010-07-19T19:04:52.280" DisplayName="csgillespie" LastAccessDate="2013-05-21T17:32:58.693" WebsiteUrl="http://www.mas.ncl.ac.uk/~ncsg3/" Location="Newcastle, United Kingdom" AboutMe="some text 8" Views="399" UpVotes="576" DownVotes="18" EmailHash="3c3eea4eda77ffe95ae18c78c3fc7e55" Age="35" />
<row Id="10" Reputation="121" CreationDate="2010-07-19T19:05:40.403" DisplayName="Pierre" LastAccessDate="2012-10-04T17:17:01.430" WebsiteUrl="http://plindenbaum.blogspot.com" Location="France" AboutMe="some text 10" Views="8" UpVotes="2" DownVotes="0" EmailHash="61200477cf8983809ec152f484750204" Age="43" />
<row Id="11" Reputation="136" CreationDate="2010-07-19T19:06:02.713" DisplayName="wahalulu" LastAccessDate="2013-05-26T20:36:24.567" WebsiteUrl="http://www.linkedin.com/in/marckvaisman" Location="Washington, DC" AboutMe="some text 11" Views="2" UpVotes="10" DownVotes="0" EmailHash="9a9a05e41ae6e3b127697967cea5f8fb" Age="39" />
<row Id="12" Reputation="101" CreationDate="2010-07-19T19:06:34.507" DisplayName="Jin" LastAccessDate="2013-04-11T18:31:58.360" WebsiteUrl="http://www.8164.org" Location="Raleigh, NC" AboutMe="some text 12" Views="5" UpVotes="4" DownVotes="0" EmailHash="70ad2c2830eb9a7753bd6312f3811e3e" Age="37" />
<row Id="13" Reputation="677" CreationDate="2010-07-19T19:06:49.527" DisplayName="Sharpie" LastAccessDate="2012-01-02T22:55:04.743" WebsiteUrl="http://www.sharpsteen.net" Location="United States" AboutMe="Undergraduate studying Environmental Engineering and Applied Mathematics." Views="37" UpVotes="44" DownVotes="1" EmailHash="a52001938ed33a87334447413cc5beaa" Age="27" />
<row Id="15" Reputation="11" CreationDate="2010-07-19T19:07:32.537" DisplayName="hannes.koller" LastAccessDate="2010-08-24T14:23:18.050" WebsiteUrl="http://soma.denkt.org" Location="Vienna, Austria" AboutMe="" Views="2" UpVotes="0" DownVotes="0" EmailHash="0ecd144e2f3d05e6ee6b89404d1d4c53" Age="34" />
<row Id="16" Reputation="101" CreationDate="2010-07-19T19:08:13.957" DisplayName="slashnick" LastAccessDate="2010-08-19T20:40:59.080" Location="London, United Kingdom" Views="2" UpVotes="7" DownVotes="0" EmailHash="5691ff74e21c78cd1563b5123254cbd6" Age="30" />
<row Id="17" Reputation="192" CreationDate="2010-07-19T19:08:28.243" DisplayName="Random" LastAccessDate="2010-09-10T07:34:36.123" AboutMe="" Views="6" UpVotes="13" DownVotes="1" EmailHash="5a3c78de1408aae57797dffd0782b992" />
<row Id="18" Reputation="128" CreationDate="2010-07-19T19:08:29.070" DisplayName="grokus" LastAccessDate="2012-08-09T15:02:00.600" WebsiteUrl="http://wikipedia.org" Location="United States" AboutMe="about me 18" Views="6" UpVotes="16" DownVotes="0" EmailHash="7d1f931327bfab7b214758be17627adc" Age="43" />
<row Id="19" Reputation="101" CreationDate="2010-07-19T19:08:45.250" DisplayName="Noah Snyder" LastAccessDate="2012-06-17T15:53:43.550" WebsiteUrl="http://sbseminar.wordpress.com" Location="New York, NY" AboutMe="about me 19" Views="11" UpVotes="2" DownVotes="0" EmailHash="895385d49eb1f04c5ee1f8d7734f3a62" Age="33" />
</users>',
asText=TRUE)

XML 只是来自 stackexchange 数据转储的 Users 表的表示:

<users>
<row Id=..... />
<row Id=..... />
.....
<row Id=..... />
</users>

到数据帧的映射就像我映射表一样。这是为我完成工作的代码:

require(XML)
require(plyr)

# insert xmlTreeParse here

r = xmlRoot(users)

attrs = c('Id', 'Reputation', 'CreationDate', 'DisplayName', 'LastAccessDate',
'WebsiteUrl', 'Location', 'AboutMe', 'Views', 'UpVotes', 'DownVotes',
'EmailHash', 'Age')

mapUserAttrs = function(x, colNames) {
t = data.frame(as.integer(x['Id']),
as.integer(x['Reputation']),
strptime(x['CreationDate'], '%Y-%m-%dT%H:%M:%OS'),
as.character(x['DisplayName']),
strptime(x['LastAccessDate'], '%Y-%m-%dT%H:%M:%OS'),
as.character(x['WebsiteUrl']),
as.character(x['Location']),
as.character(x['AboutMe']),
as.integer(x['Views']),
as.integer(x['UpVotes']),
as.integer(x['DownVotes']),
as.character(x['EmailHash']),
as.integer(x['Age']))
names(t) = colNames
return(t)
}

result = ldply(lapply(xmlChildren(r), xmlAttrs), mapUserAttrs, attrs)

对我来说它看起来太忙了 - 但我发现没有更好的方法来使用 XML 包以及我找到的大量示例和文档来完成任务。

我想知道是否有更简单(或更短)的方法来完成相同的任务?

最佳答案

您可以使用 XML 包中的 xmlToList 函数执行此操作,并且由于您的某些节点包含其他节点不包含的选项,因此您还需要plyr 包中的 rbind.fill 函数。

下面的代码行将您的 XML 转换为列表,遍历节点并将字符串转换为数据帧,然后将所有这些数据帧绑定(bind)在一起。

require(xml)
require(plyr)

out <- do.call("rbind.fill",
lapply(xmlToList(users),
function(x) as.data.frame(as.list(x), stringsAsFactors = FALSE)))


head(out)
Id Reputation CreationDate DisplayName LastAccessDate Location AboutMe Views UpVotes DownVotes
1 -1 1 2010-07-19T06:55:26.860 Community 2010-07-19T06:55:26.860 on the server farm some text 0 4382 771
2 2 101 2010-07-19T14:01:36.697 Geoff Dalgas 2012-09-13T17:41:48.300 Corvallis, OR some text 2 7 3 0
3 3 101 2010-07-19T15:34:50.507 Jarrod Dixon 2013-01-15T03:28:47.657 New York, NY some text 3 9 19 0
4 4 101 2010-07-19T19:03:27.400 Emmett 2013-04-16T16:51:04.780 New York, NY some text 4 3 0 0
5 5 6182 2010-07-19T19:03:57.227 Shane 2013-02-05T11:23:09.587 New York, NY some text 5 605 659 5
6 6 442 2010-07-19T19:04:07.647 Harlan 2013-05-09T13:11:29.027 District of Columbia some text 6 30 42 0
EmailHash WebsiteUrl Age
1 a007be5a61f6aa8f3e85ae2fc18dd66e <NA> <NA>
2 b437f461b3fd27387c5d8ab47a293d35 http://stackoverflow.com 36
3 2dfa19bf5dc5826c1fe54c2c049a1ff1 http://stackoverflow.com 34
4 129bc58fc3f1e3853cdd3cefc75fe1a0 http://minesweeperonline.com 27
5 0cee97ffd90277bf4ac753331d50af60 http://www.statalgo.com 34
6 9f1a68b9e623be5da422b44e733fa8bc http://www.harlan.harris.name 40

编辑

生成的数据框将完全由字符向量组成。如果你想将这些向量转换为日期、日期时间、数字等,你要么一个一个地做,要么你可以编写一个函数来指定哪些类应该分配给具有特定名称的列,或者您可以编写一个函数来尝试从数据中推断出正确的类。下面是最后一个选项的示例:

giveClasses <- function(df, threshold = 0.1) {
df_classes <- sapply(df, class)

df_alpha <- sapply(df, function(x) {
mean(grepl("[[:alpha:]]", x)) >= threshold}) &
df_classes == "character"

df_digits <- sapply(df, function(x) mean(grepl("\\d", x))) >= threshold &
df_classes == "character" &
!df_alpha

df_percent <- sapply(df, function(x) mean(grepl("%", x))) >= threshold &
df_classes == "character" &
!df_alpha &
df_digits

df_digits[df_percent] <- FALSE

df_decimal <- sapply(df, function(x) mean(grepl("\\.", x))) >= threshold &
df_classes == "character" &
!df_percent &
df_digits &
!df_alpha

df_dates <- sapply(df, function(x) {
mean(grepl(
"^\\d{2,4}[[:punct:]]\\d{2}[[:punct:]]\\d{2,4}$", x)) >= threshold}) &
df_classes == "character"

df_datetime <- sapply(df, function(x) {
mean(grepl(
"^\\d{2,4}[[:punct:]]\\d{2}[[:punct:]]\\d{2,4}\\D\\d{2}:\\d{2}(:\\d{2})?(\\.\\d{1,})?$", x)) >= threshold}) &
df_classes == "character"

# convert character data to appropriate classes
df_logical <- sapply(df, function(x) {
y <- unique(na.omit(x))
length(y) == 2 &
mean(grepl("^n", y, ignore.case = TRUE) |
grepl("^y", y, ignore.case = TRUE)) == 1
})

df_digits[df_dates | df_datetime] <- FALSE

df[,df_percent] <- lapply(df[,df_percent, drop = FALSE], function(x) {
as.numeric(gsub("[^[:digit:].]", "", x)) / 100})

df[,df_logical] <- lapply(df[,df_logical, drop = FALSE], function(x) {
x[grep("^y", x, ignore.case = TRUE)] <- TRUE
x[grep("^n", x, ignore.case = TRUE)] <- FALSE
as.logical(x)
})

df[,df_decimal] <- lapply(df[,df_decimal, drop = FALSE], function(x) {
as.numeric(gsub("[^[:digit:].]", "", x))})

df[,df_digits] <- lapply(df[,df_digits, drop = FALSE], function(x) {
as.integer(gsub("[^[:digit:]]", "", x))})

df[,df_dates] <- lapply(df[,df_dates, drop = FALSE], function(x) {
as.Date(x)})

df[,df_datetime] <- lapply(df[,df_datetime, drop = FALSE], function(x) {
strptime(x, '%Y-%m-%dT%H:%M:%OS')})

df_ischaracter <- sapply(df, function(x) any(class(x) == "character"))

df[,df_ischaracter] <- lapply(df[,df_ischaracter, drop = FALSE], function(x) {
x <- gsub("^\\s+|\\s+$|(?<=\\s)\\s+", "", x, perl = TRUE)})

df
}

如果该列中超过 90% 的值符合适合该类的模式,则上述函数会将一个类分配给该列。否则,它会将它们保留为字符。它解决了在您的示例数据集中找不到的模式——我只是从我正在处理的另一个项目中复制了代码。所以:

str(giveClasses(out))

'data.frame': 17 obs. of 13 variables:
$ Id : int 1 2 3 4 5 6 7 8 10 11 ...
$ Reputation : int 1 101 101 101 6182 442 329 6104 121 136 ...
$ CreationDate : POSIXlt, format: "2010-07-19 06:55:26" "2010-07-19 14:01:36" "2010-07-19 15:34:50" "2010-07-19 19:03:27" ...
$ DisplayName : chr "Community" "Geoff Dalgas" "Jarrod Dixon" "Emmett" ...
$ LastAccessDate: POSIXlt, format: "2010-07-19 06:55:26" "2012-09-13 17:41:48" "2013-01-15 03:28:47" "2013-04-16 16:51:04" ...
$ Location : chr "on the server farm" "Corvallis, OR" "New York, NY" "New York, NY" ...
$ AboutMe : chr "some text" "some text 2" "some text 3" "some text 4" ...
$ Views : int 0 7 9 3 605 30 21 399 8 2 ...
$ UpVotes : int 4382 3 19 0 659 42 14 576 2 10 ...
$ DownVotes : int 771 0 0 0 5 0 0 18 0 0 ...
$ EmailHash : chr "a007be5a61f6aa8f3e85ae2fc18dd66e" "b437f461b3fd27387c5d8ab47a293d35" "2dfa19bf5dc5826c1fe54c2c049a1ff1" "129bc58fc3f1e3853cdd3cefc75fe1a0" ...
$ WebsiteUrl : chr NA "http://stackoverflow.com" "http://stackoverflow.com" "http://minesweeperonline.com" ...
$ Age : int NA 36 34 27 34 40 27 35 43 39 ...

关于xml - 用 R 解析 XML - 总是那么困难吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17091186/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com