gpt4 book ai didi

java - 强制转义 Spring 中 XML 编码中的特殊字符

转载 作者:数据小太阳 更新时间:2023-10-29 01:59:20 29 4
gpt4 key购买 nike

我想在使用 Spring Marshaller 时强制转义特殊字符。当我使用 javax.xml.bind.Marshaller

时,下面的代码可以正常工作

读书课

package com.odr.core.action;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRegistry;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "book")
public class Book {

private String name;
private String author;
private String publisher;
private String isbn;

@XmlJavaTypeAdapter(value=CDATAAdapter.class)
private String description;

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getAuthor() {
return author;
}

public void setAuthor(String author) {
this.author = author;
}

public String getPublisher() {
return publisher;
}

public void setPublisher(String publisher) {
this.publisher = publisher;
}

public String getIsbn() {
return isbn;
}

public void setIsbn(String isbn) {
this.isbn = isbn;
}

public String getDescription() {
return description;
}

public void setDescription(String description) {
this.description = description;
}

@Override
public String toString() {
return "Book [name=" + name + ", author=" + author + ", publisher="
+ publisher + ", isbn=" + isbn + ", description=" + description
+ "]";
}
}

对象到 XML

        writer = new BufferedWriter(new FileWriter(selectedFile));
context = JAXBContext.newInstance(Book.class);
Marshaller m = context.createMarshaller();
m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

m.setProperty("com.sun.xml.bind.marshaller.CharacterEscapeHandler",
new CharacterEscapeHandler() {
@Override
public void escape(char[] ch, int start, int length,
boolean isAttVal, Writer writer)
throws IOException {
writer.write(ch, start, length);
}
});
m.marshal(book, writer);

输出:

<description>

<![CDATA[<p>With hundreds of practice questions and hands-on exercises, <b>SCJP Sun Certified Programmer for Java 6 Study Guide</b> covers what you need to know--and shows you how to prepare--for this challenging exam. </p>]]>
</description>

但是当我使用 org.springframework.oxm.jaxb.Jaxb2Marshaller 时,相同类型的代码不起作用,下面是代码

    Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
Map<String, Object> map = new HashMap<String, Object>();
map.put("jaxb.formatted.output", true);
jaxb2Marshaller.setPackagesToScan("com.odr.core.action");
// com.sun.xml.bind.characterEscapeHandler
// com.sun.xml.bind.marshaller.CharacterEscapeHandler
map.put("com.sun.xml.bind.marshaller.CharacterEscapeHandler",
new CharacterEscapeHandler() {
@Override
public void escape(char[] ac, int i, int j, boolean flag,
Writer writer) throws IOException {
writer.write(ac, i, j);
}
});
jaxb2Marshaller.setMarshallerProperties(map);

org.springframework.oxm.Marshaller marshaller = jaxb2Marshaller;
FileOutputStream fos = null;
// String fileNamePath = directory.getAbsolutePath() + "\\" + fileName;

try {
// fos = new FileOutputStream(fileNamePath);
fos = new FileOutputStream(selectedFile);
marshaller.marshal(book, new StreamResult(fos));

// File f = new File(directory,fileName);
} catch (Exception e) {
e.printStackTrace();
} finally {
if (fos != null) {
fos.close();
}
}

输出

<description>&lt;![CDATA[&lt;p&gt;With hundreds of practice questions and hands-on exercises, &lt;b&gt;SCJP Sun Certified Programmer for Java 6 Study Guide&lt;/b&gt; covers what you need to know--and shows you how to prepare--for this challenging exam. &lt;/p&gt;]]&gt;</description>

第一个片段没有对特殊字符进行编码。但是使用 Spring 的第二个片段确实进行了编码,尽管我设置了属性。为了不影响现有代码,我必须在我的项目中使用 Spring。有什么办法可以解决吗

最佳答案

好的,我遇到了同样的问题,我是这样解决的。

要事第一。您应该创建两个 bean。一个用于 Jaxb2Marshaller,另一个用于 MarshallingHttpMessageConverter。我假设您想保留您的配置,所以我将使用您的代码。

创建 Jaxb2Marshaller bean:

@Bean
public Jaxb2Marshaller getJaxb2Marshaller() {
Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
Map<String, Object> map = new HashMap<String, Object>();
map.put("jaxb.formatted.output", true);
jaxb2Marshaller.setPackagesToScan("com.odr.core.action");
map.put("com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler",
new CharacterEscapeHandler() {
@Override
public void escape(char[] ac, int i, int j, boolean flag,
Writer writer) throws IOException {
writer.write(ac, i, j);
}
});
jaxb2Marshaller.setMarshallerProperties(map);

org.springframework.oxm.Marshaller marshaller = jaxb2Marshaller;
FileOutputStream fos = null;

try {
fos = new FileOutputStream(selectedFile);
marshaller.marshal(book, new StreamResult(fos));
} catch (Exception e) {
e.printStackTrace();
} finally {
if (fos != null) {
fos.close();
}
}

return jaxb2Marshaller;
}

嗯,我正在使用 Java 8,所以我将 com.sun.xml.bind.marshaller.CharacterEscapeHandler 更改为 com.sun.xml.internal .bind.marshaller.CharacterEscapeHandler 如上所示。

创建 MarshallingHttpMessageConverter bean:

@Bean
public MarshallingHttpMessageConverter getMarshallingHttpMessageConverter() {
return new MarshallingHttpMessageConverter(getJaxb2Marshaller());
}

您一定注意到我已经创建了自己的 HttpMessageConverter 来解决这个问题。这是因为 Spring 使用它自己的转换器,每次需要将实体或 DTO 转换为 XML objetct 时,它都会创建一个新的 Marshaller 实例。所以,我认为下面的代码可以解决您的问题。希望对你有帮助。

import com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.http.converter.xml.MarshallingHttpMessageConverter;
import org.springframework.oxm.jaxb.Jaxb2Marshaller;

@Configuration
public class XmlParseConfig {
@Bean
public Jaxb2Marshaller getJaxb2Marshaller() {
Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
Map<String, Object> map = new HashMap<String, Object>();
map.put("jaxb.formatted.output", true);
jaxb2Marshaller.setPackagesToScan("com.odr.core.action");
map.put("com.sun.xml.internal.bind.marshaller.CharacterEscapeHandler",
new CharacterEscapeHandler() {
@Override
public void escape(char[] ac, int i, int j, boolean flag,
Writer writer) throws IOException {
writer.write(ac, i, j);
}
});
jaxb2Marshaller.setMarshallerProperties(map);

org.springframework.oxm.Marshaller marshaller = jaxb2Marshaller;
FileOutputStream fos = null;

try {
fos = new FileOutputStream(selectedFile);
marshaller.marshal(book, new StreamResult(fos));
} catch (Exception e) {
e.printStackTrace();
} finally {
if (fos != null) {
fos.close();
}
}

return jaxb2Marshaller;
}

@Bean
public MarshallingHttpMessageConverter getMarshallingHttpMessageConverter() {
return new MarshallingHttpMessageConverter(getJaxb2Marshaller());
}
}

关于java - 强制转义 Spring 中 XML 编码中的特殊字符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38381951/

29 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com