c# - C# 中的 XML - hasAttribute、getAttribute 不存在吗？为什么？

Question

我正在从事一个项目，该项目要求我在单独的数据库中构建游戏的房间、元素和 NPC。我选择了 XML，但有些东西阻止我在我的 C# 代码中正确解析 XML。我做错了什么？

我的错误是:

System.xml.xmlnode does not contain a definition for HasAttribute 

(这也适用于 GetAttribute)并且没有扩展方法接受 'HasAttribute' 接受类型为 System.Xml.XmlNode 的第一个参数> ？

这也适用于 GetParentNode 和我的最后一行

string isMoveableStr = xmlRoom.GetAttribute("isMoveable");

不知何故:

the name xmlRoom does not exist in the current context

方法如下:

public void loadFromFile()
    {
        XmlDocument xmlDoc = new XmlDocument();              // create an xml document object in memory.
        xmlDoc.Load("gamedata.xml");                         // load the XML document from the specified file into the object in memory.

        // Get rooms, NPCs, and items.
        XmlNodeList xmlRooms = xmlDoc.GetElementsByTagName("room");
        XmlNodeList xmlNPCs = xmlDoc.GetElementsByTagName("npc");
        XmlNodeList xmlItems = xmlDoc.GetElementsByTagName("item");

        foreach(XmlNode xmlRoom in xmlRooms) {               // defaults for room:

        string roomID = ""; 
        string roomDescription = "this a standard room, nothing special about it.";                  

        if( !xmlRoom.HasAttribute("ID") )                   //http://msdn.microsoft.com/en-us/library/acwfyhc7.aspx
        {              
        Console.WriteLine("A room was in the xml file without an ID attribute. Correct this to use the room"); 
        continue;                                       //skips remaining code in loop 

            } else {
             roomID = xmlRoom.GetAttribute("id");           //http://msdn.microsoft.com/en-us/library/acwfyhc7.aspx
            }

        if( xmlRoom.hasAttribute("description") )              
        {
            roomDescription = xmlRoom.GetAttribute("description");
        }

        Room myRoom = new Room(roomDescription, roomID); //creates a room
        rooms.Add(myRoom); //adds to list with all rooms in game ;)

            } foreach(XmlNode xmlNPC in xmlNPCs)
            { bool isMoveable = false;

        if( !xmlNPC.hasAttribute("id") )
        {
            Console.WriteLine("A NPC was in the xml file, without an id attribute, correct this to spawn the npc");
            continue; //skips remaining code in loop
        }

        XmlNode inRoom = xmlNPC.getParentNode();
        string roomID = inRoom.GetAttribute("id");

        if( xmlNPC.hasAttribute("isMoveable") )
        {
            string isMoveableStr = xmlRoom.GetAttribute("isMoveable");
            if( isMoveableStr == "true" )
            isMoveable = true;
            }

        }
    }

Answer 1

System.Xml.XmlElement 具有您正在寻找的功能。您正在获取 XMLNode 的。您需要将节点转换为 XmlElement 才能获得该功能。

xmlElement = (System.Xml.XmlElement)xmlRoom;