c# - 如何使用 DotNetZip 从 zip 中提取 XML 文件

Question

我使用的是最新版本的 DotNetZip，我有一个包含 5 个 XML 的 zip 文件。
我想打开 zip，读取 XML 文件并设置一个包含 XML 值的字符串。
我该怎么做？

代码:

//thats my old way of doing it.But I needed the path, now I want to read from the memory
string xfile = System.IO.File.ReadAllText(strNewFilePath, System.Text.Encoding.Default);

using (ZipFile zip = ZipFile.Read(this.uplZip.PostedFile.InputStream))
{
    foreach (ZipEntry theEntry in zip)
    {
        //What should I use here, Extract ?
    }
}

谢谢

Answer 1

ZipEntry 有一个 Extract() 重载，可以提取到流中。 (1)

在这个答案中混合 How do you get a string from a MemoryStream? ，你会得到这样的东西(完全未经测试):

string xfile = System.IO.File.ReadAllText(strNewFilePath, System.Text.Encoding.Default);
List<string> xmlContents;

using (ZipFile zip = ZipFile.Read(this.uplZip.PostedFile.InputStream))
{
    foreach (ZipEntry theEntry in zip)
    {
        using (var ms = new MemoryStream())
        {
            theEntry.Extract(ms);

            // The StreamReader will read from the current 
            // position of the MemoryStream which is currently 
            // set at the end of the string we just wrote to it. 
            // We need to set the position to 0 in order to read 
            // from the beginning.
            ms.Position = 0;
            var sr = new StreamReader(ms);
            var myStr = sr.ReadToEnd();
            xmlContents.Add(myStr);
        }
    }
}