xml - 将 XML 属性转换为元素 XSLT

Question

我正在尝试将属性转换为子元素，即转以下内容:

<WP featured="yes" player="no" dancers="no" series="logos" archive="no" fanart="no" id="eclipse_logos_">
    <seriesName>LOGOS</seriesName>
    <selection>ECLIPSE</selection>
    <imgurl>http://www.nba.com/warriors/photos/eclipse_logos_</imgurl>
    <res>1024x1024r(iPad/iPhone)?1280x1024r(Regular)?1440x900r(Widescreen)?1920x1080r(HDTV)?1920x1200r(Widescreen)</res>
</WP>

进入:

<WP>
    <featured>yes</featured>
    <player>no</player>
    <dancers>no</dancers>
    <series>logos</series>
    <archive>no</archive>
    <fanart>no></fanart>
    <id>eclipse_logos_</id>
    <seriesName>LOGOS</seriesName>
    <selection>ECLIPSE</selection>
    <imgurl>http://www.nba.com/warriors/photos/eclipse_logos_</imgurl>
    <res>1024x1024r(iPad/iPhone)?1280x1024r(Regular)?1440x900r(Widescreen)?1920x1080r(HDTV)?1920x1200r(Widescreen)</res>
</WP>

Answer 1

试试这个:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>

  <xsl:template match="@*">
    <xsl:element name="{name()}"><xsl:value-of select="."/></xsl:element>
  </xsl:template>
</xsl:stylesheet>