flutter - 获取容器在 Flutter 上的 "y"位置

Question

我想获得容器、小部件、堆栈等的“y”位置。当它显示在屏幕中央时，我想从图像(视频预览图像)更改为视频文件。我该怎么办？

我找到了屏幕高度。我计算了屏幕中心。我找不到容器位置。

我创建了这样一个示例，但该项目没有位于中心。可能我在这里犯了算法错误？

class _DedectCenterState extends State<DedectCenter> {

Size _wSize;
int listSize = 4;
List<GlobalKey> _key = [];

ScrollController _sController;

_scrollListener() {
 print("scrolling : " + _sController.offset.toString());

 setState(() {
   getPosition();
});}

@override
void initState() {

for(int i=0; i < listSize; i++) {
  _key[i] = new GlobalKey();
}

_sController = ScrollController();

_sController.addListener(_scrollListener);
super.initState();
}

void getPosition(){

double _wCenterTop = (_wSize.height / 2) - 150.0;
double _wCenterBottom = (_wSize.height / 2) + 150.0;

print("center bottom: " + _wCenterBottom.toString());
print("center top: " + _wCenterTop.toString());


for(int i=0; i < listSize; i++) {

  //add key to your widget, which position you need to find
  RenderBox box = _key[i].currentContext.findRenderObject();
  Offset position = box.localToGlobal(Offset.zero); //this is global position
  double y = position.dy; //this is y - I think it's what you want

   print("key $i y position: " + y.toString());

  if(y < _wCenterTop && y > _wCenterBottom) print("key $i center: " + y.toString());
 }}


Widget build(BuildContext context) {
 _wSize = MediaQuery.of(context).size;

return new Scaffold(
  appBar: null,
  body: new ListView(
    controller: _sController,
  children: <Widget>[
    Row(
      children: <Widget>[
        Column(
          children: <Widget>[
            Container(
              key: _key[0],
              margin: EdgeInsets.only(top:100.0),
              height: 140.0,
                width: _wSize.width,
                child: new Image.asset('assets/images/physical/a1.png'),
            )],)],
    ),  
    Row(
      children: <Widget>[
        Column(
          children: <Widget>[
            Container(
              key: _key[1],
              margin: EdgeInsets.only(top:100.0),
              height: 140.0,
              width: _wSize.width,
              child: new Image.asset('assets/images/physical/a2.png'),
  ),],)],
),
    Row(
      children: <Widget>[
        Column(
          children: <Widget>[
            Container(
              margin: EdgeInsets.only(top:100.0),
              key: _key[2],
              height: 140.0,
              width: _wSize.width,
                child: new Image.asset('assets/images/physical/a3.png'),
            ),],)],),
     Row(
      children: <Widget>[
        Column(
          children: <Widget>[
            Container(
              margin: EdgeInsets.only(top:100.0),
              key: _key[3],
              width: _wSize.width,
                height: 140.0,
                child: new Image.asset('assets/images/physical/a4.png'),
            ),
          ],
        )
      ],),]));}}

Answer 1

您可以使用 GlobalKey 获取小部件的大小或位置

GlobalKey key = GlobalKey(); // declare a global key

将键添加到您的小部件，您需要找到它的位置

Container(
   key: key,
   ...
); 

使用渲染框获取位置

RenderBox box = key.currentContext.findRenderObject() as RenderBox;
Offset position = box.localToGlobal(Offset.zero); //this is global position
double y = position.dy; //this is y - I think it's what you want