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java - 将 Java RSA 非对称加密转换为 Flutter Dart

转载 作者:IT王子 更新时间:2023-10-29 07:18:41 31 4
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我正在尝试将我们的安卓移动应用程序移植到 Flutter。它是用 Java 编写的。但是,在这一部分,我需要在发布到服务器之前使用 RSA 加密来加密登录凭据和卡详细信息,但我无法做到这一点。

我已经尝试了几个不起作用的 flutter 包。根据Java开发人员的说法,有一个base64编码的公钥需要用于加密密码。

这是Java代码

public  static  String Encrypt(String plaintext, String publicKey ) throws Exception {
try
{

if(StringUtils.isEmpty(plaintext)) return "";
byte[] modulusBytes = Base64.decode(publicKey.getBytes("UTF-8"),Base64.DEFAULT);
byte[] exponentBytes = Base64.decode("AQAB".getBytes("UTF-8"),Base64.DEFAULT);
BigInteger modulus = new BigInteger(1, modulusBytes );
BigInteger exponent = new BigInteger(1, exponentBytes);
RSAPublicKeySpec rsaPubKey = new RSAPublicKeySpec(modulus, exponent);
KeyFactory fact = KeyFactory.getInstance("RSA");
PublicKey pubKey = fact.generatePublic(rsaPubKey);

Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1PADDING");
cipher.init(Cipher.ENCRYPT_MODE, pubKey);

byte[] plainBytes = new String(plaintext).getBytes("UTF-8");
byte[] cipherData = cipher.doFinal( plainBytes );


String outputEncrypted = Base64.encodeToString(cipherData,Base64.NO_WRAP);

return outputEncrypted;

}catch (Exception ex)
{
Log.i("Exception", ex.getMessage());
throw ex;

}

}

如果我能得到任何帮助将其转换为 dart 以便在 flutter 代码中使用它,我将不胜感激。

更新

我尝试了@Richard Heap pointycaSTLe 加密,它似乎工作正常但服务器无法解密字符串。抛出异常

Interop+AppleCrypto+AppleCFErrorCryptographicException: The operation couldn’t be completed. (OSStatus error -2147415994 - CSSMERR_CSP_INVALID_DATA)
at Interop.AppleCrypto.ExecuteTransform(SecKeyTransform transform)
at Interop.AppleCrypto.RsaDecrypt(SafeSecKeyRefHandle privateKey, Byte[] data, RSAEncryptionPadding padding)
at System.Security.Cryptography.RSAImplementation.RSASecurityTransforms.Decrypt(Byte[] data, RSAEncryptionPadding padding)
at System.Security.Cryptography.RSACryptoServiceProvider.Decrypt(Byte[] rgb, Boolean fOAEP)


Internal.Cryptography.CryptoThrowHelper+WindowsCryptographicException: The parameter is incorrect
at Internal.NativeCrypto.CapiHelper.DecryptKey(SafeKeyHandle safeKeyHandle, Byte[] encryptedData, Int32 encryptedDataLength, Boolean fOAEP, Byte[]& decryptedData)
at System.Security.Cryptography.RSACryptoServiceProvider.Decrypt(Byte[] rgb, Boolean fOAEP

服务器上的解密方法是用C#写的

更新 2

经过数小时的谷歌搜索,我终于找到了这个 github issue on PointyCastle以及 duncanhoggan 的解决方案。结果我只需要使用 PKCS1Encoding。

  var pubKey = RSAPublicKey(modulus, exponent);
var cipher = PKCS1Encoding(RSAEngine());
cipher.init(true, PublicKeyParameter<RSAPublicKey>(pubKey));
Uint8List output = cipher.process(utf8.encode(text));
var base64EncodedText = base64Encode(output);
return base64EncodedText;

@Richard Heap,感谢您的帮助。

最佳答案

试试这个:

import 'dart:math';
import 'dart:convert';
import 'dart:typed_data';

import 'package:convert/convert.dart';
import 'package:pointycastle/api.dart';
import 'package:pointycastle/asymmetric/api.dart';
import 'package:pointycastle/asymmetric/rsa.dart';

String encrypt(String plaintext, String publicKey) {
var modulusBytes = base64.decode(publicKey);
var modulus = BigInt.parse(hex.encode(modulusBytes), radix: 16);
var exponent = BigInt.parse(hex.encode(base64.decode('AQAB')), radix: 16);
var engine = RSAEngine()
..init(
true,
PublicKeyParameter<RSAPublicKey>(RSAPublicKey(modulus, exponent)),
);

//PKCS1.5 padding
var k = modulusBytes.length;
var plainBytes = utf8.encode(plaintext);
var paddingLength = k - 3 - plainBytes.length;
var eb = Uint8List(paddingLength + 3 + plainBytes.length);
var r = Random.secure();
eb.setRange(paddingLength + 3, eb.length, plainBytes);
eb[0] = 0;
eb[1] = 2;
eb[paddingLength + 2] = 0;
for (int i = 2; i < paddingLength + 2; i++) {
eb[i] = r.nextInt(254) + 1;
}

print(plainBytes.length);
print(eb);

return base64.encode(
engine.process(eb),
);
}

关于java - 将 Java RSA 非对称加密转换为 Flutter Dart,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56473470/

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