unit-testing - flutter :测试

Question

我正在尝试测试这个功能

  UserApi createUserApi(String url, String username, String password) {
    UserApi userApi = new UserApi(base: route(url), serializers: repo);
    userApi.base.basicAuth('$username', '$password');
    return userApi;
  }

基本上，测试是将此函数的结果与它的“手动组合”进行比较，期望得到相同的结果。但事实并非如此:

  String username = "asd";
  String password = "asd";
  UserApi userApiTest = new UserApi(base: route("asd"), serializers: repo);
  userApiTest.base.basicAuth('$username', '$password');
  test("UserApi creation", () {
    UserApi userApi = _presenter.createUserApi("asd", "asd", "asd");
    expect(userApi, userApiTest);
  }); 

结果总是:

Expected: <Instance of 'UserApi'>
  Actual: <Instance of 'UserApi'>

为什么不同？在调试中，每个属性都是相同的。

Answer 1

您有两个不同的 UserApi 实例。它们具有相同的属性值并不能使它们相等。

您需要实现 hashCode 和 operator==。默认情况下，只有比较对同一对象实例的引用才被认为是相等的(因为它们是相同的)

另见

• How does a set determine that two objects are equal in dart?
• http://pchalin.blogspot.com/2014/04/defining-equality-and-hashcode-for-dart.html
• https://api.dartlang.org/stable/2.0.0/dart-core/Object/hashCode.html
• https://api.dartlang.org/stable/2.0.0/dart-core/String/operator_equals.html