flutter : url_launcher exception

Question

我正在使用 url_launcher 依赖项在我的一个图标上具有拨号功能；然而，这适用于 Android 而不是 IOS？

调用启动器方法是:

   _launchcaller()  async
  {
    const url = '719-282-2224';

    if (await canLaunch(url))
    {
      await launch(url);
    }

    else{
      throw 'Could not launch $url';
    }

  }

然后我在 onTap 监听器上调用该方法，如下所示:

new GestureDetector(

             onTap: _launchcaller,

      child: new Icon(Icons.phone, color: Colors.blue, size: 50.0,),

    ),

异常输出:

[VERBOSE-2:dart_error.cc(16)] Unhandled exception:
Could not launch tel:719-282-2224
#0      angryScreenState._launchcaller (file:///Users/ielbouyahyaouy/AndroidStudioProjects/app_firebase/flutter_app_books/lib/angryScreen.dart:103:7)
<asynchronous suspension>
#1      GestureRecognizer.invokeCallback (package:flutter/src/gestures/recognizer.dart:102:24)
#2      TapGestureRecognizer._checkUp (package:flutter/src/gestures/tap.dart:161:9)
#3      TapGestureRecognizer.handlePrimaryPointer (package:flutter/src/gestures/tap.dart:94:7)
#4      PrimaryPointerGestureRecognizer.handleEvent (package:flutter/src/gestures/recognizer.dart:315:9)
#5      PointerRouter._dispatch (package:flutter/src/gestures/pointer_router.dart:73:12)
#6      PointerRouter.route (package:flutter/src/gestures/pointer_router.dart:101:11)
#7      _WidgetsFlutterBinding&BindingBase&GestureBinding.handleEvent (package:flutter/src/gestures/binding.dart:143:19)
#8      _WidgetsFlutterBinding&BindingBase&GestureBinding.dispatchEvent (packag<…>

Answer 1

要让 iOS 设备将 url 理解为电话号码，您需要去掉破折号。你可以这样做。它也应该以 tel://为前缀

url = 'tel://719-282-2224';
url = url.replaceAll(new RegExp(r'-'), ''); // remove dashes