android - ERROR_ALREADY_REQUESTING_PERMISSIONS flutter

Question

我用 flutter 创建了一个 android 应用程序，我在应用程序运行时第一次创建权限请求，所以当用户单击拒绝然后单击登录按钮时，再次请求权限。我遇到了这个错误

Exception has occurred.
PlatformException (PlatformException(ERROR_ALREADY_REQUESTING_PERMISSIONS, A request for permissions is already running, please wait for it to finish before doing another request (note that you can request multiple permissions at the same time)., null))

这是我的代码

@override
  void initState() {
    this.setSharedPreferences();
    PermissionHandler().checkPermissionStatus(PermissionGroup.location).then(_checkPermission);
  }

void _checkPermission(PermissionStatus status){
    if(status == PermissionStatus.unknown || status == PermissionStatus.denied){
      _askPermission();
    }
  }

void _askPermission() async{
    await PermissionHandler().requestPermissions([PermissionGroup.location]);
  }

void onLogin() async {
   PermissionStatus locationPermission = await PermissionHandler().checkPermissionStatus(PermissionGroup.location);
   if(locationPermission == PermissionStatus.denied || locationPermission == PermissionStatus.unknown){
        _askPermission();
   }else{
     // user available to login
   }
}

如何处理？谢谢你的回答

Answer 1

事情是当它检查权限时它返回 null 而不是任何权限状态，这会导致异常。这可能是一个错误，很多人已经解决了与位置权限相关的问题。

https://github.com/BaseflowIT/flutter-geolocator/issues/172

https://github.com/BaseflowIT/flutter-geolocator/issues/

https://github.com/BaseflowIT/flutter-permission-handler/issues

void getPermissionStatus() async {
        PermissionStatus permission = await PermissionHandler()
            .checkPermissionStatus(PermissionGroup.storage);
        if (permission == PermissionStatus.granted) {
        } // ideally you should specify another condition if permissions is denied
else if (permission == PermissionStatus.denied ||
            permission == PermissionStatus.disabled ||
            permission == PermissionStatus.restricted) {
          await PermissionHandler().requestPermissions([PermissionGroup.storage]);
          getPermissionStatus();
        }
      }

我不认为你的代码有问题，无论如何你可以使用递归而不是创建两个单独的函数。