swift - NSOpenPanel 作为工作表

Question

我查看了其他答案，但似乎对我的情况没有任何帮助。

我有一个 viewController 类，其中包含一个按钮的 IBAction。此按钮应从该 viewController 打开一个 NSOpenPanel 作为工作表:

class ViewController: NSViewController {
@IBAction func folderSelection(sender: AnyObject) {
    var myFiledialog: NSOpenPanel = NSOpenPanel()
    myFiledialog.prompt = "Select path"
    myFiledialog.worksWhenModal = true
    myFiledialog.allowsMultipleSelection = false
    myFiledialog.canChooseDirectories = true
    myFiledialog.canChooseFiles = false
    myFiledialog.resolvesAliases = true

    //myFiledialog.runModal()

    myFiledialog.beginSheetModalForWindow(self.view.window!, completionHandler: nil)


    var chosenpath = myFiledialog.URL
    if (chosenpath!= nil)
    {
        var TheFile = chosenpath!.absoluteString!
        println(TheFile)
        //do something with TheFile
    }
    else
    {
        println("nothing chosen")
    }
}
}

问题来自 myFileDialog.beginSheetModalForWindow(..) ，它与上面的行一起工作，但这不是工作表效果

Answer 1

您需要从窗口面板调用 beginSheetModalForWindow，并使用完成 block :

let myFiledialog = NSOpenPanel()
myFiledialog.prompt = "Select path"
myFiledialog.worksWhenModal = true
myFiledialog.allowsMultipleSelection = false
myFiledialog.canChooseDirectories = true
myFiledialog.canChooseFiles = false
myFiledialog.resolvesAliases = true
myFiledialog.beginSheetModalForWindow(window, completionHandler: { num in
    if num == NSModalResponseOK {
        let path = myFiledialog.URL
        print(path)
    } else {
        print("nothing chosen")
    }
})