objective-c - NSRegularExpression 提取两个 XML 标签之间的文本

Question

如何使用 NSRegularExpression 提取“badgeCount”标签之间的值“6”。以下是服务器的响应:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?><badgeCount>6</badgeCount><rank>2</rank><screenName>myName</screenName>

以下是我试过但没有成功的代码。实际上它进入 else 部分并打印“正则表达式的值是零”:

NSString *responseString =   [[NSString alloc] initWithBytes:[responseDataForCrntUser bytes] length:responseDataForCrntUser.length encoding:NSUTF8StringEncoding];

NSError *error;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"(?<=badgeCount>)(?:[^])*?(?=</badgeCount)" options:0 error:&error];
if (regex != nil) {
    NSTextCheckingResult *firstMatch = [regex firstMatchInString:responseString options:0 range:NSMakeRange(0, [responseString length])];
    NSLog(@"NOT NIL");
    if (firstMatch) {
        NSRange accessTokenRange = [firstMatch rangeAtIndex:1];
        NSString *value = [urlString substringWithRange:accessTokenRange];
        NSLog(@"Value: %@", value);
    }
}
else
    NSLog(@"Value of regex is nil");

如果您能提供示例代码，我们将不胜感激。

注意:我不想使用 NSXMLParser。

Answer 1

例子:

NSString *xml = @"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?><badgeCount>6</badgeCount><rank>2</rank><screenName>myName</screenName>";
NSString *pattern = @"<badgeCount>(\\d+)</badgeCount>";

NSRegularExpression *regex = [NSRegularExpression
                                      regularExpressionWithPattern:pattern
                                      options:NSRegularExpressionCaseInsensitive
                                      error:nil];
NSTextCheckingResult *textCheckingResult = [regex firstMatchInString:xml options:0 range:NSMakeRange(0, xml.length)];

NSRange matchRange = [textCheckingResult rangeAtIndex:1];
NSString *match = [xml substringWithRange:matchRange];
NSLog(@"Found string '%@'", match);

NSLog输出:

Found string '6'