ios - 如何将字符串解析为 NSTimeInterval

Question

如何将字符串值如 12:02:21.3213 解析为 NSTimeInterval？ NSDateComponentsFormatter，从 iOS8 开始可用，只支持格式化，不支持解析。

Answer 1

这里是你如何在 Swift 中做到这一点，

它适用于像这样的值2:12:12，02:01:23.123213

Swift 5(@Youstanzr):

extension String {
    func convertToTimeInterval() -> TimeInterval {
        guard self != "" else {
            return 0
        }

        var interval:Double = 0

        let parts = self.components(separatedBy: ":")
        for (index, part) in parts.reversed().enumerated() {
            interval += (Double(part) ?? 0) * pow(Double(60), Double(index))
        }

        return interval
    }
}

Swift 3(作者:@Torre Lasley)

func parseDuration(_ timeString:String) -> TimeInterval {
    guard !timeString.isEmpty else {
        return 0
    }

    var interval:Double = 0

    let parts = timeString.components(separatedBy: ":")
    for (index, part) in parts.reversed().enumerated() {
        interval += (Double(part) ?? 0) * pow(Double(60), Double(index))
    }

    return interval
}

swift 2

    func parseDuration(timeString:String) -> NSTimeInterval {
        guard !timeString.isEmpty else {
            return 0
        }
        
        var interval:Double = 0
        
        let parts = timeString.componentsSeparatedByString(":")
        for (index, part) in parts.reverse().enumerate() {
            interval += (Double(part) ?? 0) * pow(Double(60), Double(index))
        }
        
        return interval
    }