ios - 如何使用swift检查iphone型号

Question

我们如何在 Swift 中检查 iPhone 型号(例如 iPhone 4/iPhone5)。使用下面的代码我可以检查它是否是 iPod 的 iPhone。

let iphoneModel = UIDevice.currentDevice().model
if (iphoneModel == "iPhone"){
        println("Iphone 4")
    }

我需要具体知道它是哪种 iPhone 型号。

Answer 1

使用以下代码。 (Reference from)

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.mainScreen().bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.mainScreen().bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

并将其用作:

if DeviceType.IS_IPHONE_6P {
            println("IS_IPHONE_6P")
}