ios - 与数组匹配的 Swift 开关模式

Question

想知道是否有办法在 Swift 中执行以下操作。

let foo = [1, 2, 3]
let bar = [4, 5, 6]

let value = 5

switch value {
case in foo
    print("5 is in foo")
case in bar
    print("5 is in bar")
default:
    break
}

我知道还有其他方法可以使这个人为设计的示例正常工作，例如 case 4, 5, 6: 或者不使用开关而是使用 bar.contains(value) 但我正在寻找一种解决方案，专门涉及与数组的开关模式匹配。谢谢!

Answer 1

怎么样:

let foo = [1, 2, 3]
let bar = [4, 5, 6]

let value = 5

switch value {
case _ where foo.contains(value):
    print("\(value) is in foo")
case _ where bar.contains(value):
    print("\(value) is in bar")
default:
    print("\(value) is not in foo or bar")
}