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有没有办法在 Swift 中列出一个类的所有变量?
例如:
class foo {
var a:Int? = 1
var b:String? = "John"
}
我想这样列出:[a:1, b:"John"]
最佳答案
如何在 Swift 3.0 中递归执行此操作:
import Foundation
class FirstClass {
var name = ""
var last_name = ""
var age = 0
var other = "abc"
func listPropertiesWithValues(reflect: Mirror? = nil) {
let mirror = reflect ?? Mirror(reflecting: self)
if mirror.superclassMirror != nil {
self.listPropertiesWithValues(reflect: mirror.superclassMirror)
}
for (index, attr) in mirror.children.enumerated() {
if let property_name = attr.label {
//You can represent the results however you want here!!!
print("\(mirror.description) \(index): \(property_name) = \(attr.value)")
}
}
}
}
class SecondClass: FirstClass {
var yetAnother = "YetAnother"
}
var second = SecondClass()
second.name = "Name"
second.last_name = "Last Name"
second.age = 20
second.listPropertiesWithValues()
结果:
Mirror for FirstClass 0: name = Name
Mirror for FirstClass 1: last_name = Last Name
Mirror for FirstClass 2: age = 20
Mirror for FirstClass 3: other = abc
Mirror for SecondClass 0: yetAnother = YetAnother
关于class - 如何在swift中列出一个类的所有变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27928279/
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