swift - 无法在 Swift 2.0 中使用类型为 (String, [String]) 的参数列表调用 `join`

Question

var specializationTitles = ["a", "b", "c", "d"]
let outputString = join(" / ", specializationTitles)

遇到错误:

Cannot invoke join with an argument list of type (String, [String])

如何解决？

Answer 1

let separator = " / "
let outputString = separator.join(specializationTitles)

使用 Xcode7beta6:

specializationTitles.joinWithString(" / ")

使用 Xcode7 发布版本:

specializationTitles.joinWithSeparator(" / ")