Swift:如何在特定字符集之后获取所有内容

Question

给定以下字符串:

var snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"

如何提取“电话:”之后的所有内容

所以在这种情况下我想要

phone = 123.456.7891

我已经试过了:

    if let range = snippet.rangeOfString("Phone:") {

        let phone = snippet.substringToIndex(range.startIndex)
        print(phone) // prints 1111 West Main Street Beverly Hills, CA 90210
    }

但这会打印之前的所有内容，我需要之后的所有内容。

Answer 1

在 Swift 4 中，使用 upperBound 和下标运算符以及开放范围:

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"

if let range = snippet.range(of: "Phone: ") {
    let phone = snippet[range.upperBound...]
    print(phone) // prints "123.456.7891"
}

或者考虑修剪空白:

if let range = snippet.range(of: "Phone:") {
    let phone = snippet[range.upperBound...].trimmingCharacters(in: .whitespaces)
    print(phone) // prints "123.456.7891"
}

---

顺便说一下，如果你想同时获取两者，正则表达式可以做到这一点:

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
let regex = try! NSRegularExpression(pattern: #"^(.*?)\s*Phone:\s*(.*)$"#, options: .caseInsensitive)
if let match = regex.firstMatch(in: snippet, range: NSRange(snippet.startIndex..., in: snippet)) {
    let address = snippet[Range(match.range(at: 1), in: snippet)!]
    let phone = snippet[Range(match.range(at: 2), in: snippet)!]
}

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有关 Swift 的早期版本，请参阅 previous revision of this answer。