ios - 如何快速绘制一个简单的圆角矩形(圆角)

Question

我设法绘制了一个矩形 :-) 但我不知道如何绘制圆角矩形。

谁能帮我解决以下如何四舍五入矩形的代码？

let canvas = UIGraphicsGetCurrentContext()
rec = CGRectMake(0, 0, 40, 40);

//var maskPath = UIBezierPath(roundedRect: rec, byRoundingCorners: .BottomLeft | .BottomRight, cornerRadii: CGSize(width: 3, height: 3))

CGContextAddRect(canvas, rec);
CGContextFillPath(canvas);

Answer 1

//把这段代码放在你的drawRect中

目标 - C

 - (void)drawRect:(CGRect)rect
{

CGContextRef ctx = UIGraphicsGetCurrentContext();
CGContextSaveGState(ctx);


 CGPathRef clippath = [UIBezierPath bezierPathWithRoundedRect:CGRectMake(x,y, width, height) cornerRadius:6].CGPath;
CGContextAddPath(ctx, clippath);

CGContextSetFillColorWithColor(ctx, self.color.CGColor);

CGContextClosePath(ctx);
CGContextFillPath(ctx);

[self.color set];


[_path closePath]; // Implicitly does a line between p4 and p1
[_path fill]; // If you want it filled, or...
[_path stroke]; // ...if you want to draw the outline.
CGContextRestoreGState(ctx);
}

swift 3

func drawRect(rect : CGRect)
{
// Size of rounded rectangle
let rectWidth = rect.width
let rectHeight = rect.height

// Find center of actual frame to set rectangle in middle
let xf:CGFloat = (self.frame.width  - rectWidth)  / 2
let yf:CGFloat = (self.frame.height - rectHeight) / 2

let ctx: CGContext = UIGraphicsGetCurrentContext()!
ctx.saveGState()

let rect = CGRect(x: xf, y: yf, width: rectWidth, height: rectHeight)
let clipPath: CGPath = UIBezierPath(roundedRect: rect, cornerRadius: rectCornerRadius).cgPath

ctx.addPath(clipPath)
ctx.setFillColor(rectBgColor.cgColor)




ctx.closePath()
ctx.fillPath()
ctx.restoreGState()

}