swift - 如何使用 CGContext 在 swift 中按程序绘制矩形/线

Question

几天来，我一直在网上搜索，试图找到有关如何在 Swift 中按程序绘制矩形或直线的最简单的代码示例。我已经了解了如何通过覆盖 DrawRect 命令来完成此操作。我相信您可以创建一个 CGContext，然后绘制成图像，但我希望看到一些简单的代码示例。或者这是一种糟糕的方法？谢谢。

class MenuController: UIViewController 
{

    override func viewDidLoad() 
    {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
        self.view.backgroundColor = UIColor.blackColor()

        var logoFrame = CGRectMake(0,0,118,40)
        var imageView = UIImageView(frame: logoFrame)
        imageView.image = UIImage(named:"Logo")
        self.view.addSubview(imageView)

        //need to draw a rectangle here
    }
}

Answer 1

下面是一个示例，它创建了一个自定义 UIImage，其中包含一个透明背景和一个带有对角线穿过它的红色矩形。

class ViewController: UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad();

        let imageSize = CGSize(width: 200, height: 200)
        let imageView = UIImageView(frame: CGRect(origin: CGPoint(x: 100, y: 100), size: imageSize))
        self.view.addSubview(imageView)
        let image = drawCustomImage(size: imageSize)
        imageView.image = image
    }
}

func drawCustomImage(size: CGSize) -> UIImage {
    // Setup our context
    let bounds = CGRect(origin: .zero, size: size)
    let opaque = false
    let scale: CGFloat = 0
    UIGraphicsBeginImageContextWithOptions(size, opaque, scale)
    let context = UIGraphicsGetCurrentContext()!

    // Setup complete, do drawing here
    context.setStrokeColor(UIColor.red.cgColor)
    context.setLineWidth(2)

    context.stroke(bounds)

    context.beginPath()
    context.move(to: CGPoint(x: bounds.minX, y: bounds.minY))
    context.addLine(to: CGPoint(x: bounds.maxX, y: bounds.maxY))
    context.move(to: CGPoint(x: bounds.maxX, y: bounds.minY))
    context.addLine(to: CGPoint(x: bounds.minX, y: bounds.maxY))
    context.strokePath()

    // Drawing complete, retrieve the finished image and cleanup
    let image = UIGraphicsGetImageFromCurrentImageContext()
    UIGraphicsEndImageContext()
    return image!
}